I've been trying to find a string in PHP that matches something like this:
Currently I've tried something like this;
<()\?php eval(^>>
but it dosen't seem to get the string correctly.
edit: I forgot to 开发者_StackOverflow中文版add that I need to grab all the text form "" and it spans multiple lines.
Why not just use Select-String?
ls *.php | Select-String "<?php eval"
The pattern given to Select-String
is read as a regular expression. You can do plain-text matching by specifying the simpleMatch
switch:
ls *.php | Select-String "<?php eval" -simpleMatch
Here's the command to get the live help for PowerShell regular expressions:
get-help about_regular_expression
EDIT:
Ah, you didn't specify in your question that you were doing a REPLACE operation. This is a bit different, especially since it spans multiple lines. I would suggest something like this:
# Retrieve file as a single string.
$contents = [string]::Join("`n", $(Get-Content path\to\file.php))
# Now replace.
$replaced = $contents -replace '(?s)(<\?php eval\()(.*?)(\)\?>)', '$1neweval$3'
So what this is doing is looking for <?php eval(
, then LAZILY (important!) looking for )?>
, all in single-line mode, so newlines are matched in the .*?
portion. (Slashes before the question marks and parens to escape them.) It then replaces all matches with group 1 (in this case, <?php eval(
), some text, then group 3 (the )?>
). You can make the grouping as complex as you need to to collect information from within the match.
Also, because you are trying to use regex to parse a language, instead of a language parser, there are lots of cases where this can go horribly, horribly wrong. Just be aware, and don't clobber your files until you've verified that the output is correct.
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