Is there something like PHP's preg_replace_callback() in javascript?

What I want to do is str.replace(pattern, callback),

not simply str.replace(pa开发者_如何学运维ttern, replace_pattern),

is it possible to do it in javascript?

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Why, yes, you can do exactly that: str.replace(pattern, function () { ... }).

Here's some documentation: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/replace#specifying_a_function_as_the_replacement

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Yes

var s2 = s1.replace(/regex/, function(whole, part1, part2, ...) { ... })

The function is passed the whole matched string as the first argument. If there are any capturing groups, those are passed as subsequent arguments.

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The general case have no solution with s1.replace(/regex/, function(whole, part1, part2, ...partN) { ... }), where you need to know all parts and it is not valid g option;

arbitrary number of itens

The example of RegExp('\{([^\}]*)\}', 'g') can be solved by a loop... Supposing the URI-template problem, replacing each placeholder by global getData dictionary.

const tpl = 'myEtc/{aa}/etc1/{bb}/etc2'
const getData = {"aa":"expandAA","bb":"expandBB"}

function expandTpl(getData,s0){  // s0 is the link_template_input
  const r = RegExp('\{([^\}]*)\}', 'g');
  let s = '';
  let idx=0
  for (let a; (a=r.exec(s0)) !== null;) {
    s   += ( s0.substring(idx, r.lastIndex-a[0].length) + getData[a[1]] )
    idx = r.lastIndex
  }
  if ( idx<s0.length ) s += s0.substring(idx,s0.length)
  return s
}

console.log( tpl )
console.log( expandTpl(getData,tpl) )