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How to Use Calculated Color Values with ColorMatrix?

开发者 https://www.devze.com 2023-01-02 18:30 出处:网络
I am changing color values of each pixel in an image based on a calculation. The problem is that this takes over 5 seconds on my machine with a 1000x1333 image and I\'m looking for a way to optimize i

I am changing color values of each pixel in an image based on a calculation. The problem is that this takes over 5 seconds on my machine with a 1000x1333 image and I'm looking for a way to optimize it to be much faster.

I think ColorMatrix may be an option, but I'm having a difficult time figure out how I would get a set of pixel RGB values, use that to calculate and then set the new pixel value. I can see how this can be done if I was just modifying (multiplying, subtracting, etc.) the original value with ColorMatrix, but now how I can use the pixels returned value to use it to calculate and new value.

For example:

Sub DarkenPicture()
    Dim clrTestFolderPath = "C:\Users\Me\Desktop\ColorTest\"
    Dim originalPicture = "original.jpg"
    Dim Luminance As Single
    Dim bitmapOriginal As Bitmap = Image.FromFile(clrTes开发者_JAVA百科tFolderPath + originalPicture)
    Dim Clr As Color
    Dim newR As Byte
    Dim newG As Byte
    Dim newB As Byte
    For x = 0 To bitmapOriginal.Width - 1
        For y = 0 To bitmapOriginal.Height - 1
            Clr = bitmapOriginal.GetPixel(x, y)
            Luminance = ((0.21 * (Clr.R) + (0.72 * (Clr.G)) + (0.07 * (Clr.B))/ 255
            newR = Clr.R * Luminance
            newG = Clr.G * Luminance
            newB = Clr.B * Luminance
            bitmapOriginal.SetPixel(x, y, Color.FromArgb(newR, newG, newB))
        Next
    Next
    bitmapOriginal.Save(clrTestFolderPath + "colorized.jpg", ImageFormat.Jpeg)
End Sub

The Luminance value is the calculated one. I know I can set ColorMatrix's M00, M11, M22 to 0, 0, 0 respectively and then put a new value in M40, M41, M42, but that new value is calculated based of a value multiplication and addition of that pixel's components (((0.21 * (Clr.R) + (0.72 * (Clr.G)) + (0.07 * (Clr.B)) and the result of that - Luminance - is multiplied by the color component).

Is this even possible with ColorMatrix?


No. Making any one of the color components being multiplied with itself or any other component is not possible with a ColorMatrix. You can ony multiply the components with constants and then add the parts together.

But what you can do is to write this into C# and use .LockBits instead of GetPixel/SetPixel. That would be even faster that what you could possibly achieve with a ColorMatrix.

UPDATE: some sample code:

    private static void myVerySpecialSepia(
        IntPtr source,
        IntPtr destination,
        int height,
        int width,
        int sourceStride,
        int destinationStride,
        int sourceBytesPerPixel,
        int destinationBytesPerPixel )
    {
        unsafe
        {
            for ( int y = 0 ; y < height ; y++ )
            {
                byte* pOrig = (byte*)source.ToPointer() + sourceStride * y;
                byte* pDest = (byte*)destination.ToPointer() + destinationStride * y;
                for ( int x = width ; x > 0 ; x-- )
                {
                    float b = pOrig[0];
                    float g = pOrig[1];
                    float r = pOrig[2];
                    float b2 = b * b;
                    float g2 = g * g;
                    float r2 = r * r;
                    pDest[0] = (byte)(
                        b * 0.400367618f + b2 * 0.00011502471f +
                        g * (-0.0337239578f) + g2 * 0.00056673412f +
                        r * 0.221445322f + r2 * 0.0008506606f +
                        6.2766808485f);
                    pDest[1] = (byte)(
                        b * 0.493460029f + b2 * (-0.00023297003f) +
                        g * (-0.008577178f) + g2 * 0.00031247039f +
                        r * 0.5043012 + r2 * (-0.00006892065f) +
                        0.2746957206f);
                    pDest[2] = (byte)(
                        b * 0.617727f + b2 * (-0.00070876251f) +
                        g * 0.00271902746f + g2 * 0.00007401942f +
                        r * 0.6954346f + r2 * (-0.00065937551f) +
                        0.116103285f);
                    pOrig += sourceBytesPerPixel;
                    pDest += destinationBytesPerPixel;
                }
            }
        }
    }
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