After using IDA Pro to disassemble a x86 dll, I found this code (Comments added by me in pusedo-c code. I hope they're correct):
test ebx, ebx ; if (ebx == false)
开发者_JAVA技巧jz short loc_6385A34B ; Jump to 0x6385a34b
mov eax, [ebx+84h] ; eax = *(ebx+0x84)
mov ecx, [esi+84h] ; ecx = *(esi+0x84)
mov al, [eax+30h] ; al = *(*(ebx+0x84)+0x30)
xor al, [ecx+30h] ; al = al XOR *(*(esi+0x84)+0x30)
jnz loc_6385A453
Lets make it simpler for me to understand:
mov eax, b3h
xor eax, d6h
jnz ...
How does the conditional jump instruction work after a xor instruction?
Like most instructions, xor
sets the processor condition flags depending on the result of the previous operation. In this case, the Z flag will be set if the result of the xor
is zero. The jnz
instruction tests the Z flag and branches if it is not set.
I barely know assembly at all but xor
in this context does pretty much the same as cmp
I’d say, in addition to setting eax
to the result of the xor operation.
In other words, after the xor
, eax
will be 0 exactly if its previous value was d6h
(otherwise, it will be some value != 0). And additionally, the zero flag will be set (as with cmp
) so you can jnz
to test that flag.
It will jump if the value in eax
doesn't end up as zero.
Your second example doesn't do the code justice since the code you have is using constant values, not values loaded from memory.
In the first example, it loads all those values from memory and performs the xor
on that. The memory contents may, unlike your second example, change on each execution depending on what's in [ebx+84h]
and [esi+84h]
.
See xor and jnz for details.
Arithmetic operations like xor set comparison flags (just like a compare instruction).
Well, JNZ is a conditional jump, specifically, jump if not zero.
the XOR (and many other arithmetic/logic operations) will set the zero flag of the status register if the result of the operation is zero. So in your case, it's saying "do XOR, and if the result is not zero (i.e. if the two numbers are different) jump to this location.
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