开发者

Android getting XML values

开发者 https://www.devze.com 2023-01-02 14:25 出处:网络
I have the following XML code, which I got by a UPnP device and like to get the res value - the RTSP URL. In this case rtsp://10.42.0.103:554/live.sdp

I have the following XML code, which I got by a UPnP device and like to get the res value - the RTSP URL. In this case rtsp://10.42.0.103:554/live.sdp

How can I do this? I heard that Android has some built-in support for reading XML. Is that true?

<DIDL-Lite xmlns="urn:schemas-upnp-org:metadata-1-0/DIDL-Lite/" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:upnp="urn:schemas-upnp-org:metadata-1-0/upnp/">
<item id="11" parentID="1" restricted="1">
<dc:title>Network Camera Stream 1</dc:title>
<upnp:class&g开发者_运维问答t;object.item.videoItem</upnp:class>
<res protocolInfo="rtsp-rtp-udp:*:video/mpeg4-generic:*" resolution="640x480">rtsp://10.42.0.103:554/live.sdp</res>
</item>
<item id="12" parentID="1" restricted="1">
<dc:title>Network Camera Stream 2</dc:title>
<upnp:class>object.item.videoItem</upnp:class>
<res protocolInfo="rtsp-rtp-udp:*:video/mpeg4-generic:*" resolution="176x144">rtsp://10.42.0.103:554/live2.sdp</res>
</item>
</DIDL-Lite>


You may probably be looking for a SAX-Parser:
http://developer.android.com/reference/javax/xml/parsers/SAXParser.html

SAXParserFactory factory = SAXParserFactory.newInstance();
SAXParser parser = factory.newSAXParser();
parser.parse(xml, yourXMLHandler);


Well, thanks for your help. SAX is in my opinion too much overhead for this small file. It's much easier with an XMLPullParser ... you don't have to deal with this event stuff and can quickly pick up some keywords ...

http://developer.android.com/reference/org/xmlpull/v1/XmlPullParser.html

0

精彩评论

暂无评论...
验证码 换一张
取 消