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using a switch statement to see which 'bin' a number falls into

开发者 https://www.devze.com 2023-01-02 11:12 出处:网络
lets say i have a bunch of bins, each of which holds a range of numbers. an example is: bin 1: 0-8 bin 2: 9-16

lets say i have a bunch of bins, each of which holds a range of numbers. an example is:

bin 1: 0-8
bin 2: 9-16
bin 3: 17-24
etc

is there a way to use a switch statement to figure out which bin a number belongs to? i'm trying to figure out how to make cases reflect that 开发者_如何学Ca number is within a range, but they don't seem to be 'constant expressions' so i'm not sure it's possible..

edit

I should probably be more accurate; my bins are powers of two...

bin 1: 0 to 2^3
bin 2: 2^3 + 1 to 2^4
bin 3: 2^4 + 1 to 2^5
etc


You can't use ranges for case labels in C - only single (constant-expression) values.

If the ranges are small, like your example, then you can do this:

switch (value)
{
    case 0: case 1: case 2: case 3: case 4: case 5: case 6: case 7: case 8:
    bin = 1;
    break;

    case 9: case 10: case 11: case 12: case 13: case 14: case 15: case 16:
    bin = 2;
    break;

    case 17: case 18: case 19: case 20: case 21: case 22: case 23: case 24:
    bin = 3;
    break;

    default:
}

Alternatively, you can use a lookup table:

static const int val_bin[] = {
    1, 1, 1, 1, 1, 1, 1, 1, 1, /* 0 to 8 */
    2, 2, 2, 2, 2, 2, 2, 2, /* 9 to 16 */
    3, 3, 3, 3, 3, 3, 3, 3 /* 17 to 24 */
};

bin = val_bin[value];

Or, in some cases, you can determine a simple formula. Your current example appears to be such a case:

bin = 1 + (value - 1 / 8);

Response to edit:

For your updated question, on powers of 2, this is actually quite easy. You can use the "bit-smearing" technique to munge all values that lie between two powers-of-two into one value (this assumes you are using unsigned long for value, with a maximum value of 2^32 - 1):

if (value > 0)
    value -= 1; /* This is needed because your specified bins are "off by one" from the natural definitions */

value |= value >> 16;
value |= value >> 8;
value |= value >> 4;
value |= value >> 2;
value |= value >> 1;

switch (value)
{
    case 0x00000000UL: /* 0, 1 */
    case 0x00000001UL: /* 2 */
    case 0x00000003UL: /* 2^1 + 1 ... 2^2 */
    case 0x00000007UL: /* 2^2 + 1 ... 2^3 */
    bin = 1;
    break;

    case 0x0000000fUL: /* 2^3 + 1 ... 2^4 */
    bin = 2;
    break;

    case 0x0000001fUL: /* 2^4 + 1 ... 2^5 */
    bin = 3;
    break;

    /* etc */
}


You can cascade them though:

case 0:case 1: case 2: case 3: case 4: ..... case 8:
    do_something();
    break;
case 9: case 10: ....... etc


If your compiler is GCC, you are lucky. GCC has an extension called case ranges, that allows you to write your switch like this:

switch (value) {
    case 0 ... 8:
        bin = 1;
        break;
    case 9 ... 16:
        bin = 2;
        break;
    /* and so on */
}

It is not standard C!

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