How d开发者_开发技巧o you divide two integers and get a double or float answer in C?
You need to cast one or the other to a float
or double
.
int x = 1;
int y = 3;
// Before
x / y; // (0!)
// After
((double)x) / y; // (0.33333...)
x / ((double)y); // (0.33333...)
Of course, make sure that you are store the result of the division in a double
or float
! It doesn't do you any good if you store the result in another int
.
Regarding @Chad's comment ("[tailsPerField setIntValue:tailsPer]
"):
Don't pass a double or float to setIntValue
when you have setDoubleValue
, etc. available. That's probably the same issue as I mentioned in the comment, where you aren't using an explicit cast, and you're getting an invalid value because a double is being read as an int.
For example, on my system, the file:
#include <stdio.h>
int main()
{
double x = 3.14;
printf("%d", x);
return 0;
}
outputs:
1374389535
because the double was attempted to be read as an int.
Use type-casting. For example,
main()
{
float a;
int b = 2, c = 3;
a = (float) b / (float) c; // This is type-casting
printf("%f", a);
}
精彩评论