In /initializers/time_formats.rb I have this:
Time::DATE_FORMATS[:profile] = "%m /开发者_StackOverflow %d / %Y"
However this obviously produces dates such as: 09 / 08 / 2001
Google tells me my best bet is to use some kind of gsub regular expression to edit out the 0's. Is this true or is there a better alternative?
@date = Time.new
@date.month #=> 10
@date.day #=> 7
@date.year #=> 2009
if you want to use format string for some parts, you can do something like:
@date.strftime("%B #{@date.day.ordinalize}, %Y") #=> October 7th, 2009
You could probably use '%e' to get the day number without the leading zero; however, the manual page for 'strftime()' - which usually underlies these time-based conversions - does not show a way to do that for the months, so the regex solution is perhaps one way to do it, though there might be other more Ruby-idiomatic ways to achieve the equivalent result.
You can use a lambda/proc as a format in Time::DATE_FORMATS, e.g.
Loading development environment (Rails 2.3.4)
>> Time::DATE_FORMATS[:my_format] = lambda { |time| "#{time.day}/#{time.month}/#{time.year}" }
=> #<Proc:0x000000010341a2e0@(irb):3>
>> 2.months.ago.to_s(:my_format)
=> "8/8/2009"
Note that the default Time::DATE_FORMATS uses a lambda for both the :long_ordinal
and :rfc822
formats.
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