Looking for quick, simple way in Java to change thi开发者_高级运维s string

" hello     there   "

to something that looks like this

"hello there"

where I replace all those multiple spaces with a single space, except I also want the one or more spaces at the beginning of string to be gone.

Something like this gets me partly there

String mytext = " hello     there   ";
mytext = mytext.replaceAll("( )+", " ");

but not quite.

Try this:

String after = before.trim().replaceAll(" +", " ");

No `trim()` regex

It's also possible to do this with just one replaceAll, but this is much less readable than the trim() solution. Nonetheless, it's provided here just to show what regex can do:

    String[] tests = {
        "  x  ",          // [x]
        "  1   2   3  ",  // [1 2 3]
        "",               // []
        "   ",            // []
    };
    for (String test : tests) {
        System.out.format("[%s]%n",
            test.replaceAll("^ +| +$|( )+", "$1")
        );
    }

There are 3 alternates:

^_+ : any sequence of spaces at the beginning of the string
- Match and replace with $1, which captures the empty string
_+$ : any sequence of spaces at the end of the string
- Match and replace with $1, which captures the empty string
(_)+ : any sequence of spaces that matches none of the above, meaning it's in the middle
- Match and replace with $1, which captures a single space

First it will replace all the spaces with single space. Than we have to supposed to do trim String because Starting of the String and End of the String it will replace the all space with single space if String has spaces at Starting of the String and End of the String So we need to trim them. Than you get your desired String.

String blogName = "how to   do    in  java   .         com"; 
 
String nameWithProperSpacing = blogName.replaceAll("\\\s+", " ");

trim()

Removes only the leading & trailing spaces.

From Java Doc, "Returns a string whose value is this string, with any leading and trailing whitespace removed."

System.out.println(" D ev  Dum my ".trim());

"D ev Dum my"

replace(), replaceAll()

Replaces all the empty strings in the word,

System.out.println(" D ev  Dum my ".replace(" ",""));

System.out.println(" D ev  Dum my ".replaceAll(" ",""));

System.out.println(" D ev  Dum my ".replaceAll("\\s+",""));

Output:

"DevDummy"

"DevDummy"

"DevDummy"

Note: "\s+" is the regular expression similar to the empty space character.

Reference : https://www.codedjava.com/2018/06/replace-all-spaces-in-string-trim.html

In Kotlin it would look like this

val input = "\n\n\n  a     string with     many    spaces,    \n"
val cleanedInput = input.trim().replace(Regex("(\\s)+"), " ")

A lot of correct answers been provided so far and I see lot of upvotes. However, the mentioned ways will work but not really optimized or not really readable. I recently came across the solution which every developer will like.

String nameWithProperSpacing = StringUtils.normalizeSpace( stringWithLotOfSpaces );

You are done. This is readable solution.

You could use lookarounds also.

test.replaceAll("^ +| +$|(?<= ) ", "");

test.replaceAll("^ +| +$| (?= )", "")

<space>(?= ) matches a space character which is followed by another space character. So in consecutive spaces, it would match all the spaces except the last because it isn't followed by a space character. This leaving you a single space for consecutive spaces after the removal operation.

Example:

    String[] tests = {
            "  x  ",          // [x]
            "  1   2   3  ",  // [1 2 3]
            "",               // []
            "   ",            // []
        };
        for (String test : tests) {
            System.out.format("[%s]%n",
                test.replaceAll("^ +| +$| (?= )", "")
            );
        }

See String.replaceAll.

Use the regex "\s" and replace with " ".

Then use String.trim.

String str = " hello world"

reduce spaces first

str = str.trim().replaceAll(" +", " ");

capitalize the first letter and lowercase everything else

str = str.substring(0,1).toUpperCase() +str.substring(1,str.length()).toLowerCase();

you should do it like this

String mytext = " hello     there   ";
mytext = mytext.replaceAll("( +)", " ");

put + inside round brackets.

String str = "  this is string   ";
str = str.replaceAll("\\s+", " ").trim();

This worked for me

scan= filter(scan, " [\\s]+", " ");
scan= sac.trim();

where filter is following function and scan is the input string:

public String filter(String scan, String regex, String replace) {
    StringBuffer sb = new StringBuffer();

    Pattern pt = Pattern.compile(regex);
    Matcher m = pt.matcher(scan);

    while (m.find()) {
        m.appendReplacement(sb, replace);
    }

    m.appendTail(sb);

    return sb.toString();
}

The simplest method for removing white space anywhere in the string.

 public String removeWhiteSpaces(String returnString){
    returnString = returnString.trim().replaceAll("^ +| +$|( )+", " ");
    return returnString;
}

check this...

public static void main(String[] args) {
    String s = "A B  C   D    E F      G\tH I\rJ\nK\tL";
    System.out.println("Current      : "+s);
    System.out.println("Single Space : "+singleSpace(s));
    System.out.println("Space  count : "+spaceCount(s));
    System.out.format("Replace  all = %s", s.replaceAll("\\s+", ""));

    // Example where it uses the most.
    String s = "My name is yashwanth . M";
    String s2 = "My nameis yashwanth.M";

    System.out.println("Normal  : "+s.equals(s2));
    System.out.println("Replace : "+s.replaceAll("\\s+", "").equals(s2.replaceAll("\\s+", "")));

}

If String contains only single-space then replace() will not-replace,

If spaces are more than one, Then replace() action performs and removes spacess.

public static String singleSpace(String str){
    return str.replaceAll("  +|   +|\t|\r|\n","");
}

To count the number of spaces in a String.

public static String spaceCount(String str){
    int i = 0;
    while(str.indexOf(" ") > -1){
      //str = str.replaceFirst(" ", ""+(i++));
        str = str.replaceFirst(Pattern.quote(" "), ""+(i++)); 
    }
    return str;
}

Pattern.quote("?") returns literal pattern String.

My method before I found the second answer using regex as a better solution. Maybe someone needs this code.

private String replaceMultipleSpacesFromString(String s){
    if(s.length() == 0 ) return "";

    int timesSpace = 0;
    String res = "";

    for (int i = 0; i < s.length(); i++) {
        char c = s.charAt(i);

        if(c == ' '){
            timesSpace++;
            if(timesSpace < 2)
                res += c;
        }else{
            res += c;
            timesSpace = 0;
        }
    }

    return res.trim();
}

Stream version, filters spaces and tabs.

Stream.of(str.split("[ \\t]")).filter(s -> s.length() > 0).collect(Collectors.joining(" "))

I know replaceAll method is much easier but I wanted to post this as well.

public static String removeExtraSpace(String input) {
    input= input.trim();
    ArrayList <String> x= new ArrayList<>(Arrays.asList(input.split("")));
    for(int i=0; i<x.size()-1;i++) {
        if(x.get(i).equals(" ") && x.get(i+1).equals(" ")) { 
            x.remove(i); 
            i--; 
        }
    }
    String word="";
    for(String each: x) 
        word+=each;
    return word;
}

String myText = "   Hello     World   ";
myText = myText.trim().replace(/ +(?= )/g,'');


// Output: "Hello World"

string.replaceAll("\s+", " ");

If you already use Guava (v. 19+) in your project you may want to use this:

CharMatcher.whitespace().trimAndCollapseFrom(input, ' ');

or, if you need to remove exactly SPACE symbol ( or U+0020, see more whitespaces) use:

CharMatcher.anyOf(" ").trimAndCollapseFrom(input, ' ');

public class RemoveExtraSpacesEfficient {

    public static void main(String[] args) {

        String s = "my    name is    mr    space ";

        char[] charArray = s.toCharArray();

        char prev = s.charAt(0);

        for (int i = 0; i < charArray.length; i++) {
            char cur = charArray[i];
            if (cur == ' ' && prev == ' ') {

            } else {
                System.out.print(cur);
            }
            prev = cur;
        }
    }
}

The above solution is the algorithm with the complexity of O(n) without using any java function.

Please use below code

package com.myjava.string;

import java.util.StringTokenizer;

public class MyStrRemoveMultSpaces {

    public static void main(String a[]){

        String str = "String    With Multiple      Spaces";

        StringTokenizer st = new StringTokenizer(str, " ");

        StringBuffer sb = new StringBuffer();

        while(st.hasMoreElements()){
            sb.append(st.nextElement()).append(" ");
        }

        System.out.println(sb.toString().trim());
    }
}