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:contains for multiple words

开发者 https://www.devze.com 2023-01-01 05:24 出处:网络
I am using the f开发者_Go百科ollowing jQuery var etag = \'kate\' if (etag.length > 0) { $(\'div\').each(function () {

I am using the f开发者_Go百科ollowing jQuery

var etag = 'kate'
if (etag.length > 0) {
    $('div').each(function () {
        $(this).find('ul:not(:contains(' + etag + '))').hide();
        $(this).find('ul:contains(' + etag + ')').show();
    });
}​

towards the following HTML

<div id="2">
<ul>
  <li>john</li>
  <li>jack</li>
</ul>
<ul>
  <li>kate</li>
  <li>clair</li>
</ul>
<ul>
  <li>hugo</li>
  <li>desmond</li>
</ul>  
<ul>
  <li>said</li>
  <li>jacob</li>
</ul>
  </div>

    <div id="3">
<ul>
  <li>jacob</li>
  <li>me</li>
</ul>
<ul>
  <li>desmond</li>
  <li>george</li>
</ul>
<ul>
  <li>allen</li>
  <li>kate</li>
</ul>  
<ul>
  <li>salkldf</li>
  <li>3kl44</li>
</ul>
</div>

basically, as long as etag has one word, the code works perfectly and hides those elements who do not contain etag. My problem is, when etag is multiple words (and I don't have control over it. Its coming from a database and could be combination of multiple words separated with space char) then the code does not work..

is there any way to achieve this?


This filter checks if any of the words in the given string match the text of the element.

jQuery.expr[':'].containsAny = function(element, index, match) {
    var words = match[3].split(/\s+/);
    var text = $(element).text();
    var results = $.map(words, function(word) {
        return text === word;
    });
    return $.inArray(true, results) !== -1;
};

Show and hide as:

$('ul').hide();
$('li:containsAny(john kate)').parents('ul').show();

See an example here.


You could turn this into a function that takes any number of words separated by a character, like this:

function filter(words) {
    var uls = $('div ul').hide();
    $.each(words.split(' '), function(i, v) {
        uls = uls.filter(':contains(' + v + ')');
    });
    uls.show();
}

//sample call
var etag='kate clair'
filter(etag);

You can see a working demo here

This finds <ul> elements that contain all the words in the given string.


Another approach:

var etag='Some text from server';

if (etag.length > 0) {
    $('div ul').each(function () {
        var el = $(this); // Local reference
        (el.html() === etag) ? el.show() : el.hide(); 
    });
}​


A slightly different approach - try this:

    var etag='kate test blah';

    var tags = etag.split(' ');
    $('div ul').each(function () {
      var list = $(this);
      list.hide();
      list.children('li').each(function() {
        var item = $(this);
        if ($.inArray(item.html(), tags) >= 0) list.show();
      });
    });

Written in the browser, so sorry if there are any bugs!

-- edit --

Actually, I reread the question, and that code won't work. You need to define the behaviour more first - does the list have to contain all of the tags, or just one of the tags to be shown?

-- edit 2 --

Code updated. Kind of inefficient, but it should do the job.

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