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ajax strange error with sending multiple parameter

开发者 https://www.devze.com 2023-01-01 00:49 出处:网络
please check with me where is the error in this ajax code to send 2 parameters: var xhr = getXhr(); // On défini ce qu\'on va faire quand on aura la réponse

please check with me where is the error in this ajax code to send 2 parameters:

var xhr = getXhr();
// On défini ce qu'on va faire quand on aura la réponse
xhr.onreadystatechange = function(){
    // On ne fait quelque chose que si on a tout reçu et que le serveur est ok
    if(xhr.readyS开发者_JAVA百科tate == 4 && xhr.status == 200)
        {
        selects = xhr.responseText;
        // On se sert de innerHTML pour rajouter les options a la liste
        //document.getElementById('prjsel').innerHTML = selects;
        }
        };
        xhr.open("POST","ServletEdition",true);
          xhr.setRequestHeader('Content-Type','application/x-www-form-urlencoded');
          id=document.getElementById(idIdden).value;
          fu=document.getElementById("formUpdate").value;
          //alert(fu);
          var i=1;
          xhr.send("id=" +id+", fu="+i);

i cant got the value of fu i don't know why. thanks


The contents of your xhr.send() need to be URL encoded. For example:

xhr.send("id=1&fu=2");

Basicallly, anything that goes inside the xhr.send() would be the same as the query string you'd set with a GET. In other words, what you have inside send should also work on the end of a URL:

http://www.mysite.com/path/to/script?id=1&fu=2


it is really strange because i am used to work with it like that. so i changed to the next:

xhr.send( "id="+id+"&fu="+i);

and it works.

thanks for help.

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