I'm not so sure how to write this: I want to generate a random number from 0 to 2, then write an if
statement which executes specific code only 33% of the time.
This is what I tried to do:
if (rand(0, 3)==开发者_运维技巧"2") { echo "Success" };
The two arguments represent the minimum and maximum random values. If you want a 1-in-3 chance, you should only allow 3 possibilities. Going from minimum 0 to maximum 3 allows 4 possible values (0,1,2,3), so that won't quite do what you want. Also, mt_rand()
is a better function to use than rand()
.
So it'd be:
if (mt_rand(1, 3) == 2)
echo "Success";
PHP's rand()
limits are inclusive, so you'd want if(rand(0,2) == 2)
.
which executes specific code only 33% of the time.
Just want to point out that using random will only give the code a 33% chance of executing as opposed to running it 1/3 of the time.
Your code will execute 25% of the time. {0 1 2 3} is a set of 4 numbers. you want to do
if(rand(1,3)==2)...
Replace with
if (rand(0, 2)==2) { echo "Success"; }
I know this is a late answer, but I'd do
if(!rand(0,2))
{
//do stuff
}
for any fraction 1/x
desired, replace 0,2
with 0,x-1
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