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Determining whether jQuery has not found any element

开发者 https://www.devze.com 2022-12-31 17:28 出处:网络
I\'m using jQuery\'s selectors, especially id selector: $(\"#elementId\")... How should I determine whether jQuery has f开发者_开发问答ound the element or not?

I'm using jQuery's selectors, especially id selector:

$("#elementId")...

How should I determine whether jQuery has f开发者_开发问答ound the element or not? Even If the element with the specified id doesn't exist the next statement give me: [object Object]

alert($("#idThatDoesnotexist"));


$('#idThatDoesnotexist').length is what you're looking for. (If it finds nothing, this will === 0.) So your conditional statement should probably be:

if($('#id').length) { /* code if found */ } else { /* code if not found */ }

You're getting an object returned from that alert because jQuery (almost) always returns the "jQuery object" when you use it, which is a wrapper for the elements jQuery's found that permits method chaining.


Futuraprime is right but you can shorten your syntax by doing the following:

if ($("#id").length) {
   //at least one element was found
} else {
   //no elements found
}


!$.isEmptyObject($.find('#id'))

This will return true if the element exists and false if it doesn't.


$('#my_selector').length > 0 
$('#my_selector').get(0) !== undefined
$('#my_selector')[0] !== undefined

This is the basic, now do whatever you want.

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