I'm having issues trying to deserializing my xml string that was from a dataset..
Here is the XML layout..
<DataSet>
<User>
<UserName>Test</UserName>
<Email>test@test.com</Email>
<Details>
<ID>1</ID>
<Name>TestDetails</Name>
<Value>1</Valu开发者_开发问答e>
</Details>
<Details>
<ID>2</ID>
<Name>Testing</Name>
<Value>3</Value>
</Details>
</User>
</DataSet>
Now I am able to deserialize the "UserName" and "Email" when doing
public class User
{
public string UserName {get;set;}
public string Email {get;set;}
public Details[] Details {get;set;}
}
public class Details
{
public int ID {get;set;}
public string Name {get;set;}
public string Value {get;set;}
}
This deserializes fine when I just get the user node, the Details isnt null but has no items in it..
i know I am suppose to have between all the details but I rather not modify the XML, anyways to get this to deserialize properly without recreating the XML after I get it?
I assume you are trying to use XmlSerializer? If so, you just need to add the [XmlElement]
attribute to the Details member. This might not seem intuitive, but this tells the serializer that you want to serialize/deserialize the array items as elements rather than an array with the items as child elements of the array.
Here is a quick example
public Test()
{
string xml = @"<DataSet>
<User>
<UserName>Test</UserName>
<Email>test@test.com</Email>
<Details>
<ID>1</ID>
<Name>TestDetails</Name>
<Value>1</Value>
</Details>
<Details>
<ID>2</ID>
<Name>Testing</Name>
<Value>3</Value>
</Details>
</User>
</DataSet>";
XmlSerializer xs = new XmlSerializer(typeof(DataSet));
DataSet ds = (DataSet)xs.Deserialize(new StringReader(xml));
}
[Serializable]
public class DataSet
{
public User User;
}
[Serializable]
public class User
{
public string UserName { get; set; }
public string Email { get; set; }
[XmlElement]
public Details[] Details { get; set; }
}
[Serializable]
public class Details
{
public int ID { get; set; }
public string Name { get; set; }
public string Value { get; set; }
}
Use the XmlElement
attribute on the Details
property :
public class User
{
public string UserName {get;set;}
public string Email {get;set;}
[XmlElement]
public Details[] Details {get;set;}
}
If you don't, the XmlSerializer
assumes that your <Details>
elements are wrapped in a parent <Details>
element
Use Linq To XML.. something like this
XElement xe = XDocument.Load("PATH_HERE").Root;
var v = from k in xe.Descendants()
select new {
id = k.Element("id"),
data = k.Element("data")
};
Here's a sample program which makes no changes to the XML but deserializes the Details node properly:
using System;
using System.Text;
using System.Xml;
using System.Xml.Linq;
using System.Xml.Serialization;
using System.IO;
using System.Diagnostics;
using System.Collections.Generic;
namespace ConsoleApplication1
{
[System.Xml.Serialization.XmlRootAttribute(Namespace = "",
IsNullable = false)]
public class DataSet
{
public User User { get; set; }
}
public class User
{
public string UserName { get; set; }
public string Email { get; set; }
[System.Xml.Serialization.XmlElementAttribute("Details")]
public Details[] Details { get; set; }
}
public class Details
{
public int ID { get; set; }
public string Name { get; set; }
public string Value { get; set; }
}
class Program
{
static void Main(string[] args)
{
string xmlFragment =
@"<DataSet>
<User>
<UserName>Test</UserName>
<Email>test@test.com</Email>
<Details>
<ID>1</ID>
<Name>TestDetails</Name>
<Value>1</Value>
</Details>
<Details>
<ID>2</ID>
<Name>Testing</Name>
<Value>3</Value>
</Details>
</User>
</DataSet>";
StringReader reader = new StringReader(xmlFragment);
XmlSerializer xs = new XmlSerializer(typeof(DataSet));
DataSet ds = xs.Deserialize(reader) as DataSet;
User user = ds.User;
Console.WriteLine("User name: {0}", user.UserName);
Console.WriteLine("Email: {0}", user.Email);
foreach (Details detail in user.Details)
{
Console.WriteLine("Detail [ID]: {0}", detail.ID);
Console.WriteLine("Detail [Name]: {0}", detail.Name);
Console.WriteLine("Detail [Value]: {0}", detail.Value);
}
// pause program execution to review results...
Console.WriteLine("Press enter to exit");
Console.ReadLine();
}
}
}
You need to do something like:
using System.IO;
using System.Xml.Serialization;
namespace TestSerialization
{
class Program
{
static void Main(string[] args)
{
string content= @"<DataSet>
<User>
<UserName>Test</UserName>
<Email>test@test.com</Email>
<Details>
<Detail>
<ID>1</ID>
<Name>TestDetails</Name>
<Value>1</Value>
</Detail>
<Detail>
<ID>2</ID>
<Name>Testing</Name>
<Value>3</Value>
</Detail>
</Details>
</User>
</DataSet>";
XmlSerializer serializaer = new XmlSerializer(typeof(DataSet));
DataSet o = (DataSet) serializaer.Deserialize(new StringReader(content));
}
}
public class User
{
public string UserName { get; set; }
public string Email { get; set; }
public Detail[] Details { get; set; }
}
public class Detail
{
public int ID { get; set; }
public string Name { get; set; }
public string Value { get; set; }
}
public class DataSet
{
public User User;
}
}
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