I have v1
and v2
, how should I got a new v
like below?
v1 = {1,2}
v2 = {3,4,5}
v = {f(1,3) , f(1,4) , f开发者_开发知识库(1,5) f(2,3) ,f(2,4) ,f(2,5)}
I know I could do it using two loops, But If there is more idiomatic way like using STL algorithm?
//using two loops
for iter1 of v1
for iter2 of v2
v.push_back(f(v1,v2))
EDIT:
v1
and v2
not necessary have same size.
There is no appropriate STL algorithm, but this combination possible to do by a custom function and std::generate:
#include <vector>
#include <algorithm>
#include <iostream>
#include <iterator>
typedef int T;
struct Fctor
{
typedef std::vector<T>::iterator Iterator;
Iterator it1, it2, begin, end;
Fctor(Iterator begin1, Iterator end1, Iterator begin2)
{
begin = begin1;
end = end1;
it1 = begin1;
it2 = begin2;
}
T operator()()
{
// T result = f(*it1, *it2);
T result = (*it1) * (*it2);
if(++it1 != end) return result;
it1 = begin;
++ it2;
return result;
}
};
int main()
{
std::vector<T> v1; v1.push_back(1); v1.push_back(2);
std::vector<T> v2; v2.push_back(3); v2.push_back(4); v2.push_back(5);
std::vector<T> result(v1.size() * v2.size());
Fctor fctor(v2.begin(), v2.end(), v1.begin());
generate(result.begin(), result.end(), fctor);
std::copy(result.begin(), result.end(),
std::ostream_iterator<T>(std::cout, " "));
std::cout << std::endl;
// => 3 4 5 6 8 10
}
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