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Groovy Grails, How do you stream or buffer a large file in a Controller's response?

开发者 https://www.devze.com 2022-12-30 16:53 出处:网络
I have a controller that makes a connection to a url to retrieve a csv file. I am able to send the file in the response using the following code, this works fine.

I have a controller that makes a connection to a url to retrieve a csv file.

I am able to send the file in the response using the following code, this works fine.

    def fileURL = "www.mysite.com/input.csv"
    def thisUrl = new URL(fileURL);
    def connection = thisUrl.openConnection();
    def output = connection.content.text;

    response.setHeader "Content-disposition", "attachment;
    filename=${'output.csv'}"
    response.contentType = 'text/csv'
    response.outputStream << output
    response.outputStream.flush()

However I think this method is inappropriate for a large file, as the whole file is loaded into the controllers memory.

I want to be ab开发者_C百科le to read the file chunk by chunk and write the file to the response chunk by chunk.

Any ideas?


Groovy OutputStreams can take InputStreams directly with the << operator. The OutputStream will pull the data automatically with an appropriately sized buffer.

The following should efficiently copy the data, even if the CSV is quite large.

def fileURL = "www.mysite.com/input.csv"
def thisUrl = new URL(fileURL);
def connection = thisUrl.openConnection();
def cvsInputStream = connection.inputStream

response.setHeader "Content-disposition", "attachment;
filename=${'output.csv'}"
response.contentType = 'text/csv'
response.outputStream << csvInputStream
response.outputStream.flush()
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