Is there a version of os.getcwd() that doesn't dereference symlinks? [duplicate]

This question already has answers her开发者_JS百科e: Closed 10 years ago.

Possible Duplicate:

How to get/set logical directory path in python

I have a Python script that I run from a symlinked directory, and I call os.getcwd() in it, expecting to get the symlinked path I ran it from. Instead it gives me the "real" path, and in this case that's not helpful. I need it to actually give me the symlinked version.

Does Python have a command for that?

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Workaround: os.getenv('PWD')

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In general this is not possible. os.getcwd() calls getcwd(3), and according to POSIX.1-2008 (IEEE Std 1003.1-2008):

The pathname shall contain no components that are dot or dot-dot, or are symbolic links.

os.getenv['PWD'] is shell-dependent and will not work for example with sh from FreeBSD.