How do I enumerate the content of a zipped folder in Java?

ZipeFile file = new ZipFile(filename);
ZipEntry folder = this.file.getEntry("some/path/in/zip/");
if (folder == null || !folder.isDirectory())
  throw new Exception();

// now, how do I enumerate the contents of the开发者_StackOverflow中文版 zipped folder?

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It doesn't look like there's a way to enumerate ZipEntry under a certain directory.

You'd have to go through all ZipFile.entries() and filter the ones you want based on the ZipEntry.getName() and see if it String.startsWith(String prefix).

String specificPath = "some/path/in/zip/";

ZipFile zipFile = new ZipFile(file);
Enumeration<? extends ZipEntry> entries = zipFile.entries();
while (entries.hasMoreElements()) {
    ZipEntry ze = entries.nextElement();
    if (ze.getName().startsWith(specificPath)) {
        System.out.println(ze);
    }
}

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You don't - at least, not directly. ZIP files are not actually hierarchical. Enumerate all the entries (via ZipFile.entries() or ZipInputStream.getNextEntry()) and determine which are within the folder you want by examining the name.

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Can you just use entries()? API link