I'm trying to construct a 开发者_如何学Pythondictionary that contains a series of sets:
{Field1:{Value1, Value2, Value3}, Field2{Value4}}
The trouble is, I then wish to delete any fields from the dictionary that only have one value in the set. I have been writing code like this:
for field in FieldSet:
if len(FieldSet[field]) == 1:
del(FieldSet[field])
But receive the error "RuntimeError: dictionary changed size during execution". (Not surprising, since that's what I'm doing.) It's not the be-all and end-all if I have to knock together some sort of workaround, but is it possible to do this?
Iterate over the return value from .keys()
instead. Since you get a list of keys back, it won't be affected by changing the dictionary after you've called it.
A sometimes-preferable alternative to changing FieldSet
in place is sometimes (depending on the amount of alterations performed) to build a new one and bind it to the existing name:
FieldSet = dict((k, v) for k, v in FieldSet.iteritems()
if len(v) != 1)
There is the pop method. It removes the element that a key calls. With respect to your example this looks like:
for field in FieldSet.keys():
if len(FieldSet[field]) == 1:
FieldSet.pop(field)
This is in python 3.2, but I'm not sure if it's a new feature: http://docs.python.org/dev/library/stdtypes.html#dict.pop
Just tried it and it works as advertised.
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