I have a serialized string comming in with POST:
$imgdata = $_POST['imgdata']; // li[]=2&li[]=3&li[]=1&li[]=4
In this example 001 is reordered after 003 How can I update my XML file with this new order? I think I need simpleXML or xpath. Here are my thoughts:
// 1. load xml string
$xml = simplexml_load_file('test.xml');
/*
<?xml version="1.0" encoding="UTF-8"?>
<gallery>
<album>
<img src="001.jpg" caption="First caption" />
<img src="002.jpg" caption="Second caption" />
<img src="003.jpg" caption="3th caption" />
<img src="004.jpg" caption="4th caption" />
</album>
</gallery>
*/
/开发者_JAVA技巧/ 2. sort nodes
// $new_xml_string = "......";
// 3. write out new XML file
$handle = fopen("images.xml", 'w');
fwrite($handle, $new_xml_string);
fclose($handle);
Changing the order of nodes amounts to the transformation of XML. You can do something like this,
<?php
$temp = <<<EOT
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:output method="xml" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="node() | @*">
<xsl:copy>
<xsl:apply-templates select="node() | @*">
<xsl:sort select="@src"/>
</xsl:apply-templates>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
EOT;
$xml = new DOMDocument;
$xml->loadXML($oldXml);
$xsl = new DOMDocument;
$xsl->loadXML($temp);
$proc = new XSLTProcessor;
$proc->importStyleSheet($xsl); // attach the xsl rules
$newXml = $proc->transformToXML($xml);
XSLT is a right way but you can use XPath+array. First step - select keys (attributes or anything else), put them into an array, then sort it with standard PHP methods. Second step - use the array as a key map to make new XML.
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