How can I do this with the JS replace() method:
- Make \n\n change to
<p>$1</p>
- Change single \n to
<br>
- Then back again. I think I have this part, see the JS at the bottom.
Example HTML:
<p>Hello</p><p>Wor<br>ld</p>
The <textarea>
would look like:
Hello
Wor
ld
So, how can I achieve this? It's an AJAX form where when you click on this div it changes to a <textarea>
and back, and fourth, etc. So, I need to it to go from <p>
s and <br>
s to \n\n
and \n
. For the going to <textarea>
from HTML I have:
$(this).html().replace(/\s?<\/?(p|br\s?\/?)>\s?/g,"\n")
to Victor, and others,
I tried this code to convert it back, but it gave me this in return (the ... is just a lot more text)
$(this).html().replace(/\n/g, "<br>").replace(/<br><br>(.*)?/g, "<p>$1</p>");
gave me:
<div class="editable" data-name="notes-content" data-type="textarea">
“Time Certain” indicates that an item will not be heard by Council prior to the time certain
.<p>Communications items are three minutes each开发者_如何学C. ...
<br><br>The * indicates an emergency ...
<br><br>Check our Web site: www.portlandonline.com
<br>
</p>
</div>
If you notice, it didnt wrap the first line, and its not wrapping them in <p>
s, just the entire thing, i need it all in <p>
s
How about this (version #4):
$(this).html().replace(/\n/g, "<br>").replace(/(.+?)<br><br>/g, "<p>$1</p>");
Here you go:
$(this).html().replace(/\n/g, "<br>").replace(/<br><br>(.*)?/g, "<p>$1</p>");
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