How to pass Model from a view to a partial view?

I have a view that is not strongly typed. However I have in this view a partial view that is strongly typed.

How do I do I pass the model to this strongly typed view?

I tried something like

 public ActionResult Test()
        {
              MyData = new Data();
              MyData.One = 1;
              return View("Test",MyData)
        }

In my TestView

<% Html.RenderPartial("PartialView",Model); %>

This give me a stackoverflow exception. So I am not sure how to pass it on. Of course I don't want to make the test view strongly typed if possible as what happens if I had like 10 strongly typed partial views 开发者_如何学运维in that view I would need like some sort of wrapper.

---

You should extend your model so that it can provide all necessary fields for the view (this is called ViewModel) or you provide them seperately with ViewData.

 public ActionResult Test()
        {
              MyData = new Data();
              MyData.One = 1;
              ViewData["someData"]=MyData;
              return View();
        }

then:

<% Html.RenderPartial("PartialView",ViewData["someData"]); %>

ViewData is a nice losely typed dictionary

---

Put the object required by the partial into Viewdata and use ist in the view as input for the partial.

public ActionResult Test()
        {
              ViewData["DataForPartial"] = new PartialDataObject();
              return View("Test")
        }

In the view use:

<% Html.RenderPartial("PartialView",ViewData["DataForPartial"]); %>

But anyway: There is no reason no to have a stronly typed view.