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Passing the Class<T> in java of a generic list?

开发者 https://www.devze.com 2022-12-29 12:34 出处:网络
I have a method for reading JSON from a service, I\'m using Gson to do my serialization and have written the following method using type parameters.

I have a method for reading JSON from a service, I'm using Gson to do my serialization and have written the following method using type parameters.

public T getDeserializedJSON(Class<T> aClass,String url)
{
    Reader r = getJSONDataAsReader(url);
    Gson gson = new Gson();
    return gson.fromJson(r, aCla开发者_运维知识库ss);
}

I'm consuming json which returns just an array of a type e.g.

[
 { "prop":"value" }
 { "prop":"value" }
]

I have a java class which maps to this object let's call it MyClass. However to use my method I need to do this:

RestClient<ArrayList<MyClass>> restClient = new RestClient<ArrayList<MyClass>>();
ArrayList<MyClass> results = restClient.getDeserializedJSON(ArrayList<MyClass>.class, url);

However, I can't figure out the syntax to do it. Passing just ArrayList.class doesn't work.

So is there a way I can get rid of the Class parameter or how do I get the class of the ArrayList of MyClass?


You can use Bozho's solution, or avoid the creation of a temporary array list by using:

Class<List<MyClass>> clazz = (Class) List.class;

The only problem with this solution is that you have to suppress the unchecked warning with @SuppressWarnings("unchecked").


You can't. You'd have to use unsafe cast:

Class<List<MyClass>> clazz = 
   (Class<List<MyClass>>) new ArrayList<MyClass>().getClass();


As a follow up to this, I found this in the Gson docs.

Type listType = new TypeToken<List<String>>() {}.getType();

Which solves the problem of getting the type safely but the TypeToken class is specific to Gson.


If you are using SpringFramework you could use ParameterizedTypeReference as follows:

 restClient.getDeserializedJSON(ParameterizedTypeReference<List<MyClass>>(){},url);


I had a similar scenario but I have a workaround to use an array instead of ArrayList

MyClass[] results = restClient.getDeserializedJSON(MyClass[].class, url);

And here what deserialize method does

You can then proceed with list as follows:

List<MyClass> r_results= Arrays.stream(results).collect(Collectors.toList());


Depending on how is your requirement, but if you are ok working with array there you can provide as Class: MyClass[].class

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