How do you declare a vector in c++ while allowing user input to define the vector's name? Okay, after reviewing your responses, here is more detail; Here is the error message from VS08 C++ console application -
Error 2 error C2664: 'std::basic_istream<_Elem,_Traits> &std::basic_istream<_Elem,_Traits>::get(_Elem *,std::s开发者_StackOverflowtreamsize)' : cannot convert parameter 1 from 'std::istream' to 'char *' e:\c++\project 5\project 5\project 5.cpp 58 project 5
Here is the code:
void addRecord()
{
vector<char>recordName;
vector<inventory>recordNameUser;
cout << "Name the record you want to store it as\n";
cin.get(cin, recordName);
cout << "Enter the item description\n";
cin.get(cin, recordNameUser.itemDescription);
cout << "Enter the quanity on hand\n";
cin >> recordNameUser.quanityOnHand;
cout << "Enter the wholesale cost\n";
cin >> recordNameUser.wholesaleCost;
cout << "Enter the retail cost\n";
cin >> recordNameUser.retailCost;
cout << "Enter the date of the inventory (mm/dd/yyyy)\n";
cin >> recordNameUser.inventoryDate;
}
What are you really trying to do?
Normally, users don't care about the variable names. What you can do is store different vectors with different user defined keys:
map<string, vector<int> > user_vectors;
while (true) {
string key = GetNameFromUserInput();
int value = GetValueFromUserInput();
user_vectors[key].push_back(value);
}
From your edited problem description, you really don't have a need for vectors at all.
map<string, inventory> inventory_map;
while (!done) {
string item_name;
cin >> item_name;
inventory item;
cin >> item.itemDescription;
cin >> item.quantityOnHand;
...;
inventory_map[item_name] = item;
}
for (map<string, inventory>::const_iterator it = inventory_map.begin();
it != inventory_map.end(); ++it) {
cout << "Inventory contains: " << it->first
<< " described as: " << it->second.description;
}
You want to have users give you a name and to be able to associate that with a vector of things? That's what a std::map
is for, with a std::string
as the key type and a std::vector
as the payload type.
You mean you want the variable's name to be read from the user? You can't do that, and there isn't really a reason to; variable names only exist for the programmer's convenience; they don't even exist in the executable unless necessary
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