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Regex Help matching quotes

开发者 https://www.devze.com 2022-12-29 01:24 出处:网络
I havin a reg ex problemm i would like to have a reg ex that will match the \'\\nGOat the end of my file(see below.) I have got the following so far:开发者_JAVA百科

I havin a reg ex problemm i would like to have a reg ex that will match the '\nGO at the end of my file(see below.) I have got the following so far:开发者_JAVA百科

^\'*GO

but its match the quote sysbol?

EOF:

WHERE     (dbo.Property.Archived <> 1)
'
GO


In Perl \Z matches the end of the string, totally ignoring line breaks. Use this to match GO on the last line of a file if the file is loaded into a string:

^GO\Z

POSIX regex uses \' instead of \Z.

To match exactly the newline and then the word GO in your example, you want this:

\nGO

You can also do this:

\n.*GO

This last regular expression will match what you want in your example, but the .* part will make it so there can be anything (or nothing) in between the newline and GO.

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