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Why the valid looking statement gives error in MATLAB?

开发者 https://www.devze.com 2022-12-28 22:34 出处:网络
It\'s from this question。 Why the two solutions doesn\'t work, though it looks very valid for me: >> t = -pi:0.1:pi;

It's from this question。

Why the two solutions doesn't work, though it looks very valid for me:

>> t = -pi:0.1:pi;
>> r = ((sin(t)*sqrt(cos(t)))*(sin(t) + (7/5))^(-1)) - 2*sin(t) + 2 ;
??? Error using ==> mtimes
Inner matrix dimensions must agree.

>> t = -pi:0.1:pi;
>> r = ((sin(t).*sqrt(cos(t))开发者_如何学运维).*(sin(t) + (7/5)).^(-1)) - 2*sin(t) + 2 ;
>> plot(r,t)
??? Error using ==> plot
Vectors must be the same lengths.

What's wrong with the above?


The * operator is the matrix multiplication operator, which requires its operands to have matching inner matrix dimensions. The .* operator is the element-wise multiplication operator, which requires its operands to have the same size (or for one to be a scalar) so it can perform multiplication on each matching pair of elements. See this link for more detail.

Also, I don't get the plotting error you do when I run the second solution. I just get this warning:

Warning: Imaginary parts of complex X and/or Y arguments ignored
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