Is it possible to set a default value for a variable argument list in Python 3?
Something like:
def do_it(*args=(2, 5, 21开发者_StackOverflow中文版)):
pass
I wonder that a variable argument list is of type tuple
but no tuple is accepted here.
If not syntactically, then depending on what behavior you want:
def do_it(*args):
if not args: args = (2, 5, 21)
or
def do_it(a=2, b=5, c=21, *args):
args = (a,b,c)+args
should do it.
Initializing a list like that usually isn't a good idea.
The default value is evaluated only once. This makes a difference when the default is a mutable object such as a list, dictionary, or instances of most classes. For example, the following function accumulates the arguments passed to it on subsequent calls
def f(a, L=[]):
L.append(a)
return L
print f(1)
print f(2)
rint f(3)
This will print
[1]
[1, 2]
[1, 2, 3]
- Stolen from: http://www.network-theory.co.uk/docs/pytut/DefaultArgumentValues.html
I generally check it something is passed in and if not then init it in the function body.
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