I have a structure usually containing a pointer to an int
. However, in some special cases, it is necessary that this int pointer points to another pointer which then points to an int. Wow: I mentioned the word pointer 5 times so far!
- Is this even possible? 开发者_运维知识库
I thought about it that way: Instead of using a second int pointer, which is most likely not possible as my main int pointer can only point to an int and not to another int pointer, I could make it a reference like this:
int intA = 1;
int intB = 2;
int& intC = intB;
int* myPointers[ 123 ];
myPointers[ 0 ] = &intA;
myPointers[ 1 ] = &intB;
myPointers[ 3 ] = &intC;
So the above would do what I want: The reference to intB
(intC
) behaves quite like I want it to (If it gets changed it also changes intB
)
- The problem: I can't change references once they are set, right? Or is there a way?
Everything in short: How do I get a value to work with *
(pointers) and **
(pointers to pointers)?
int*
and int**
are different types so you can't use one as the other without using a potentially non-portable cast.
In the declaration:
int& intC = intB;
The reference intC
will always refer to the int
intB
. The binding cannot be changed.
You could use a union to support a type that could be either an int*
or an int**
but you would need to be certain when you're reading, which member of the union is valid at any point.
union PIntOrPPInt
{
int* pint;
int** ppint;
};
int intA;
int intB;
int* pintC = &intB;
PIntOrPPInt myPointers[ 123 ];
myPointers[ 0 ].pint = &intA;
myPointers[ 1 ].pint = &intB;
myPointers[ 3 ].ppint = &pintC;
You could put a pointer to intB
in both array elements:
myPointers[ 1 ] = &intB;
myPointers[ 3 ] = &intB;
This way both elements point to the same variable and *myPointers[1]
will always be the same as *myPointers[3]
. Is this what you want to achieve?
We rarely if ever use pointers to pointers in C++. Instead, like you suggest, we use reference to pointers. That said, C++ is a strongly-typed, static-typed language. So you have to decide at compile-time what your array elements are going to point to.
One approach is to wrap the array elements in a class:
struct P {
P() : p(0) { }
P(int* p) : p(p) { }
P(int** p) : p(*p) { }
operator int*() const { return p; }
int *p;
};
int main(int argc, char* argv[])
{
int *i1 = new int(5);
int **i2 = &i1;
int *&i3 = i1;
P arr[4] = {i1, i2, i3, P()};
delete i1;
return 0;
}
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