let's say we have a class
class MyClass {
vector<vector<int > > myMatrice;
public :
MyClass(vector<vector<int > > &);
}
MyClass::MyClass(vector<vector<int > > & m) {
myMatrice = m;
}
During the instanciation of MyClass, I pass a big vector < vector < int > > and I find that the object is actually copied and not only the reference, so it takes the double of the memory ...
Please, can anyone help me out with this problem, I'm stuck since too many time ...
And thanks a lot开发者_如何转开发!
If you only want a reference then use a reference:
class MyClass {
vector<vector<int> >& myMatrice;
public:
MyClass(vector<vector<int> >& m) : myMatrice(m) {}
};
Note however that you now have to watch out that for the life-time of MyClass
- if the vector you passed a reference to in is destroyed before the MyClass
instance you are left with a dangling reference.
If you actually want shared ownership you should consider using a shared pointer (like boost::shared_ptr
or std::tr1::shared_ptr
) to a heap-allocated object.
If you truly want your "MyClass" to refer to the original vector you need to declare its member variable as a reference also.
You'll also be forced to use initialization syntax rather than assignment.
You can transfer the contents of one vector to another using swap
.
std::vector<int> a, b;
fillVector(a);
a.swap(b);
Most commonly (as above) this is used to swap an fresh (empty) container with a filled one. That requirement is met more smoothly by rvalue references in C++1x, which you may already have access to depending on what C++ compiler you're using.
Whatever you do, resist the temptation to use a non-const reference in writing a copy constructor (or assignment operator). This is the road to hell, a.k.a. auto_ptr
. It is tempting in your case:
MyClass(vector<vector<int> > &m)
{
myMatrix.swap(m);
}
But it is extremely surprising that a copy constructor would modify the object passed to it ("modify" is a polite way to describe completely gutting it!) Instead, provide a differently named member function, to make it clear that it will modify the parameter passed to it.
Besides what others are proposing, you may avoid the copy by using swap
:
class MyClass {
vector<vector<int > > myMatrice;
public :
MyClass(vector<vector<int > > &);
}
MyClass::MyClass(vector<vector<int > > & m) {
myMatrice.swap(m);
}
Note that this will garble the original vector (that is the one passed by the caller - after the constructor call, it will be empty and the data will be transfered to the myMatrice
member), so use cautiously. If you're C++0x positive, you can use rvalue-reference pretty much the same way.
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