regex: find the part, which doesn't contain none of some words

how can i much the sentense, if it doesn't contain none of {word1,word2,word3} where i must 开发者_JAVA百科put ^ symbol? i think it must looks like this

^([^word1|word2|word3])$

but it doesn't work. could you help? thanks

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Regex isn't the best tool for testing these sorts of conditions, but if you must then you can do it with negative lookaheads:

^(?!.*word1)(?!.*word2)(?!.*word3).*$

What you are trying to do won't work because [^...] is a negative character class with an unordered list of characters. What you wrote is equivalent to:

^([^123dorw|])$

Note also that depending on your needs you might also want to include word-boundaries in your regular expression:

^(?!.*\bword1\b)(?!.*\bword2\b)(?!.*\bword3\b).*$

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im not familiar with the use of regex in htaccess, so my thoughts may be bit high level:

what you try looks like kind of: if sentence contains not word1 | not word2 | not word3 then do something

i would suggest a solution the way: if sentence contains word1|word2|word3 then do nothing else do something

means don't use the negation in the "query", but in the result, which makes the regex simpler.