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Gradient borders

开发者 https://www.devze.com 2022-12-28 11:27 出处:网络
I\'m trying to apply a gradient to a border, I thought it was as simple as doing this: border-color: -moz-linear-gradient开发者_开发技巧(top, #555555, #111111);

I'm trying to apply a gradient to a border, I thought it was as simple as doing this:

border-color: -moz-linear-gradient开发者_开发技巧(top, #555555, #111111);

But this does not work.

Does anyone know what is the correct way to do border gradients?


The border-image property can accomplish this. You'll need to specify border-style and border-width too.

border-image: linear-gradient(#f6b73c, #4d9f0c) 30;
border-width: 4px;
border-style: solid;

Read more on MDN.


instead of borders, I would use background gradients and padding. same look, but much easier, more supported.

a simple example:

.g {
background-image: -webkit-gradient(linear, left bottom, left top, color-stop(0.33, rgb(14,173,173)), color-stop(0.67, rgb(0,255,255)));
background-image: -moz-linear-gradient(center bottom, rgb(14,173,173) 33%, rgb(0,255,255) 67% );
padding: 2px;
}

.g > div { background: #fff; }
<div class="g">
    <div>bla</div>
</div>


EDIT: You can also leverage the :before selector as @WalterSchwarz pointed out:

body {
    padding: 20px;
}
.circle {
    width: 100%;
    height: 200px;
    background: linear-gradient(to top, #3acfd5 0%, #3a4ed5 100%);
    border-radius: 100%;
    position: relative;
    text-align: center;
    padding: 20px;
    box-sizing: border-box;
}
.circle::before {
    border-radius: 100%;
    content: '';
    background-image: linear-gradient(to bottom, #3acfd5 0%, #3a4ed5 100%);
    top: -10px;
    left: -10px;
    bottom: -10px;
    right: -10px;
    position: absolute;
    z-index:-1;
}
<div class="circle"></div>


border-image-slice will extend a CSS border-image gradient

This (as I understand it) prevents the default slicing of the "image" into sections - without it, nothing appears if the border is on one side only, and if it's around the entire element four tiny gradients appear in each corner.

body{
  border: 16px solid transparent;
  border-image: linear-gradient(45deg, red , yellow);
  border-image-slice: 1;
  height: 120px;
  border-radius: 10px;  /* will have no effect */
}


Mozilla currently only supports CSS gradients as values of the background-image property, as well as within the shorthand background.

— https://developer.mozilla.org/en/CSS/-moz-linear-gradient

Example 3 - Gradient Borders

border: 8px solid #000;
-moz-border-bottom-colors: #555 #666 #777 #888 #999 #aaa #bbb #ccc;
-moz-border-top-colors: #555 #666 #777 #888 #999 #aaa #bbb #ccc;
-moz-border-left-colors: #555 #666 #777 #888 #999 #aaa #bbb #ccc;
-moz-border-right-colors: #555 #666 #777 #888 #999 #aaa #bbb #ccc;
padding: 5px 5px 5px 15px; 

— http://www.cssportal.com/css3-preview/borders.htm


Try this, works fine on web-kit

.border { 
    width: 400px;
    padding: 20px;
    border-top: 10px solid #FFFF00;
    border-bottom:10px solid #FF0000;
    background-image: 
        linear-gradient(#FFFF00, #FF0000),
        linear-gradient(#FFFF00, #FF0000)
    ;
    background-size:10px 100%;
    background-position:0 0, 100% 0;
    background-repeat:no-repeat;
}
<div class="border">Hello!</div>


You can achieve this without removing the border radius with background, background-clip, and background-origin:

<style>
.border-gradient-rounded {
  /* Border */
  border: 4px solid transparent;
  border-radius: 20px;
  background: 
    linear-gradient(to right, white, white), 
    linear-gradient(to right, red , blue); 
  background-clip: padding-box, border-box;
  background-origin: padding-box, border-box;
  
  /* Other styles */
  width: 100px;
  height: 40px;
  padding: 12px;
}
</style>

<div class="border-gradient-rounded">
  Content
</div>

Basically, this positions the white background over the gradient background, clips the white background from the inner border, and clips the gradient background from the outer border. This is why you need to define the border as solid transparent.

Credit to Method 2 from this dev.to post.


It's a hack, but you can achieve this effect in some cases by using the background-image to specify the gradient and then masking the actual background with a box-shadow. For example:

p {
  display: inline-block;
  width: 50px;
  height: 50px;
  /* The background is used to specify the border background */
  background: -moz-linear-gradient(45deg, #f00, #ff0);
  background: -webkit-linear-gradient(45deg, #f00, #ff0);
  /* Background origin is the padding box by default.
  Override to make the background cover the border as well. */
  -moz-background-origin: border;
  background-origin: border-box;
  /* A transparent border determines the width */
  border: 4px solid transparent;
  border-radius: 8px;
  box-shadow:
    inset 0 0 12px #0cc, /* Inset shadow */
    0 0 12px #0cc, /* Outset shadow */
    inset -999px 0 0 #fff; /* The background color */
}

From: http://blog.nateps.com/the-elusive-css-border-gradient


Try the below example:

.border-gradient {
      border-width: 5px 5px 5px 5px;
      border-image: linear-gradient(45deg, rgba(100,57,242,1) 0%, rgba(242,55,55,1) 100%);
      border-image-slice: 9;
      border-style: solid;
}


The most straight forward way is to use border-image property. You can use whatever linear-gradient or repeat-gradient you want. The border-image slice property needs to be 1 for linear gradient.

.gradient-border {
    border-style: solid;
    border-width: 2px;
    border-image: linear-gradient(45deg, red, blue) 1;
}

References MDN - https://developer.mozilla.org/en-US/docs/Web/CSS/border-image-slice digital ocean - https://www.digitalocean.com/community/tutorials/css-gradient-borders-pure-css


Try this, it worked for me.

div{
  border-radius: 20px;
  height: 70vh;
  overflow: hidden;
}

div::before{
  content: '';
  display: block;
  box-sizing: border-box;
  height: 100%;

  border: 1em solid transparent;
  border-image: linear-gradient(to top, red 0%, blue 100%);
  border-image-slice: 1;
}
<div></div>

The link is to the fiddle https://jsfiddle.net/yash009/kayjqve3/1/ hope this helps


Webkit supports gradients in borders, and now accepts the gradient in the Mozilla format.

Firefox claims to support gradients in two ways:

  1. Using border-image with border-image-source
  2. Using border-right-colors (right/left/top/bottom)

IE9 has no support.


I agree with szajmon. The only problem with his and Quentin's answers is cross-browser compatibility.

HTML:

<div class="g">
    <div>bla</div>
</div>

CSS:

.g {
background-image: -webkit-linear-gradient(300deg, white, black, white); /* webkit browsers (Chrome & Safari) */
background-image: -moz-linear-gradient(300deg, white, black, white); /* Mozilla browsers (Firefox) */
filter: progid:DXImageTransform.Microsoft.gradient(startColorstr='#ffffff', endColorstr='#000000', gradientType='1'); /* Internet Explorer */
background-image: -o-linear-gradient(300deg,rgb(255,255,255),rgb(0,0,0) 50%,rgb(255,255,255) 100%); /* Opera */
}

.g > div { background: #fff; }


Another hack for achieving the same effect is to utilize multiple background images, a feature that is supported in IE9+, newish Firefox, and most WebKit-based browsers: http://caniuse.com/#feat=multibackgrounds

There are also some options for using multiple backgrounds in IE6-8: http://www.beyondhyper.com/css3-multiple-backgrounds-in-non-supportive-browsers/

For example, suppose you want a 5px-wide left border that is a linear gradient from blue to white. Create the gradient as an image and export to a PNG. List any other CSS backgrounds after the one for the left border gradient:

#theBox {
    background:
        url(/images/theBox-leftBorderGradient.png) left no-repeat,
        ...;
}

You can adapt this technique to top, right, and bottom border gradients by changing the background position part of the background shorthand property.

Here is a jsFiddle for the given example: http://jsfiddle.net/jLnDt/


Gradient Borders from Css-Tricks: http://css-tricks.com/examples/GradientBorder/

.multbg-top-to-bottom {
  border-top: 3px solid black;
  background-image: -webkit-gradient(linear, 0 0, 0 100%, from(#000), to(transparent));
  background-image: -webkit-linear-gradient(#000, transparent);
  background-image:
      -moz-linear-gradient(#000, transparent),
      -moz-linear-gradient(#000, transparent);
  background-image:
      -o-linear-gradient(#000, transparent),
      -o-linear-gradient(#000, transparent);
  background-image: 
      linear-gradient(#000, transparent),
      linear-gradient(#000, transparent);
  -moz-background-size: 3px 100%;
  background-size: 3px 100%;
  background-position: 0 0, 100% 0;
  background-repeat: no-repeat; 
}


Example for Gradient Border

Using border-image css property

Credits to : border-image in Mozilla

.grad-border {
  height: 1px;
  width: 85%;
  margin: 0 auto;
  display: flex;
}
.left-border, .right-border {
  width: 50%;
  border-bottom: 2px solid #695f52;
  display: inline-block;
}
.left-border {
  border-image: linear-gradient(270deg, #b3b3b3, #fff) 1;
}
.right-border {
  border-image: linear-gradient(90deg, #b3b3b3, #fff) 1;
}
<div class="grad-border">
  <div class="left-border"></div>
  <div class="right-border"></div>
</div>


For cross-browser support you can try as well imitate a gradient border with :before or :after pseudo elements, depends on what you want to do.


try this code

.gradientBoxesWithOuterShadows { 
height: 200px;
width: 400px; 
padding: 20px;
background-color: white; 

/* outer shadows  (note the rgba is red, green, blue, alpha) */
-webkit-box-shadow: 0px 0px 12px rgba(0, 0, 0, 0.4); 
-moz-box-shadow: 0px 1px 6px rgba(23, 69, 88, .5);

/* rounded corners */
-webkit-border-radius: 12px;
-moz-border-radius: 7px; 
border-radius: 7px;

/* gradients */
background: -webkit-gradient(linear, left top, left bottom, 
color-stop(0%, white), color-stop(15%, white), color-stop(100%, #D7E9F5)); 
background: -moz-linear-gradient(top, white 0%, white 55%, #D5E4F3 130%); 
}

or maybe refer to this fiddle: http://jsfiddle.net/necolas/vqnk9/


Here's a nice semi cross-browser way to have gradient borders that fade out half way down. Simply by setting the color-stop to rgba(0, 0, 0, 0)

.fade-out-borders {
min-height: 200px; /* for example */

-webkit-border-image: -webkit-gradient(linear, 0 0, 0 50%, from(black), to(rgba(0, 0, 0, 0))) 1 100%;
-webkit-border-image: -webkit-linear-gradient(black, rgba(0, 0, 0, 0) 50%) 1 100%;
-moz-border-image: -moz-linear-gradient(black, rgba(0, 0, 0, 0) 50%) 1 100%;
-o-border-image: -o-linear-gradient(black, rgba(0, 0, 0, 0) 50%) 1 100%;
border-image: linear-gradient(to bottom, black, rgba(0, 0, 0, 0) 50%) 1 100%;
}

<div class="fade-out-border"></div>

Usage explained:

Formal grammar: linear-gradient(  [ <angle> | to <side-or-corner> ,]? <color-stop> [, <color-stop>]+ )
                              \---------------------------------/ \----------------------------/
                                Definition of the gradient line         List of color stops  

More here: https://developer.mozilla.org/en-US/docs/Web/CSS/linear-gradient


Here's a gradient border with transparent background that works with border-radius

.gradient-border {
  border-radius: 999px;
  padding: 10px 3rem;
  display: inline-block;
  position: relative;
  background: transparent;
  border: none;
}

.gradient-border::before {
  content: "";
  position: absolute;
  inset: 0;
  padding: 2px;
  border-radius: 9999px;
  background: linear-gradient(87.36deg, blue 6.42%, red 84.24%),
linear-gradient(0deg, #FFFFFF, #FFFFFF);
  -webkit-mask: 
     linear-gradient(#fff 0 0) content-box, 
     linear-gradient(#fff 0 0);
          mask: 
     linear-gradient(#fff 0 0) content-box, 
     linear-gradient(#fff 0 0);
  -webkit-mask-composite: xor;
          mask-composite: exclude;
}

Live demo: https://jsfiddle.net/jbernier/0eypxc74/1/


There is a nice css tricks article about this here: https://css-tricks.com/gradient-borders-in-css/

I was able to come up with a pretty simple, single element, solution to this using multiple backgrounds and the background-origin property.

.wrapper {
  background: linear-gradient(#222, #222), 
              linear-gradient(to right, red, purple);
  background-origin: padding-box, border-box;
  background-repeat: no-repeat; /* this is important */
  border: 5px solid transparent;
}

The nice things about this approach are:

  1. It isn’t affected by z-index
  2. It can scale easily by just changing the width of the transparent border

Check it out: https://codepen.io/AlexOverbeck/pen/axGQyv?editors=1100

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