How can I call parents constructor ?
module C
attr_accessor :c, :cc
def initialization c, cc
@c, @cc = c, cc
end
end
class B
attr_accessor :b, :bb
def initia开发者_StackOverflowlization b, bb
@b, @bb = b, bb
end
end
class A < B
include C
attr_accessor :a, :aa
def initialization (a, b, c, aa, bb, cc)
#call B::initialization - ?
#call C::initialization - ?
@a, @aa = a, aa
end
end
Thanks.
Ruby doesn't have constructors, therefore it's obviously not possible to call them, parent or otherwise. Ruby does have methods, however, and in order to call the parent's method with the same name as the currently executing method, you can use the super
keyword. [Note: super
without arguments is a shortcut for passing the same arguments that were passed into the currently executing method. If you actually want to pass no arguments, you have to do so explicitly: super()
.]
Use the super
method! Ruby does not have multiple inheritance though.
class B
attr_accessor :b, :bb
def initialize(b, bb)
@b, @bb = b, bb
end
end
module C
end
class A < B
include C # <= if C was a class, you'd get: TypeError: wrong argument type Class (expected Module)
attr_accessor :a, :aa
def initialize(a,b,aa,bb)
@a, @aa = a, aa
super(b, bb) # <= calls B#initialize
end
end
a = A.new(1,2,3,4)
puts a.inspect # => #<A:0x42d6d8 @aa=3, @a=1, @b=2, @bb=4>
First, your method should be initialize
, not initialization
. Then, you can use super
to call the parent class method. As for calling C
's initializer in A
, for clarity, I'd recommend splitting the initialization stuff into a different function, then just calling that function directly. It's easy to implement, and clearer.
This code below will print :
A.proc1 B.proc1 C.proc1
module A
def proc1
puts "A.proc1"
super
end
end
class B
def proc1
puts "B.proc1"
end
end
class C < B
include A
def proc1
super
puts "C.proc1"
end
end
C.new.proc1
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