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Is variable assignment and reading atomic operation?

开发者 https://www.devze.com 2022-12-28 09:18 出处:网络
I was unable to find any reference to this in the documentations... Is assigning to a double (or any other simple type, including boolean) an atomic operation viewed from the perspective of threads?

I was unable to find any reference to this in the documentations...

Is assigning to a double (or any other simple type, including boolean) an atomic operation viewed from the perspective of threads?

double value = 0;

public void First() {
 while(true) {
  value = (new Random()).NextDouble();
 }
}

public void Second() {
 while(true) {
  Console.WriteLine(value);
 }
}

In this code sample, first method is called in one thread, and the second in another. Can the second method get a messed up value if it gets its execution during assignment to the variable in another thread?

I don't care if I receive the old 开发者_运维百科value, it's only important to receive a valid value (not one where 2 out of 8 bytes are set). I know it's a stupid question, but I want to be sure, cause I don't know how CLR actually sets the variables.


To answer your question, no. Assignments to doubles are not guarenteed to be atomic. The docs are available here. Basically, <= 32-bit built-in types are atomic, >= 64-bit types aren't. For atomic operations on 64bit types, you can use the methods on System.Threading.Interlocked

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