Make windows open with work with my application

I wrote an application which will be able to open files of particular extension and show it to users. Now I want the users to be able to just double click the file and have it open with my application. I tried to set the "Always use the selected program..." option in the windows "Open With" dialog box, but do not know how to receive the file name 开发者_如何学编程that Windows sends to my application. How to do this?

Thanks...

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The file name will be passed to your application as an argument. For example, in c#, you will get it like this:

static class Program

[STAThread]
static void Main(string[] args)
{
  if (args.Length > 0)
  {
    string filename = args[0];
  }
}

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If I understood well, you need something like:

~ Notepad test.txt 

So, you need to make an optional argument in your application. If it exists open the file. If not, open a new file.

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You should receive the filename in your application's startup parameters

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Windows passes the filename as a startup parameter to your application. You will need to handle this in your WinMain or application entry point.