I need to authenticate users from database, Spring Security documents don't开发者_JAVA技巧 tell how to authenticate with hibernate. Is that possible and how can I do that?
You have to make your own custom authentication-provider.
Example code:
Service to load Users from Hibernate:
import org.springframework.security.core.userdetails.UserDetails;
import org.springframework.security.core.userdetails.UserDetailsService;
import org.springframework.security.core.userdetails.UsernameNotFoundException;
@Service("userDetailsService")
public class UserDetailsServiceImpl implements UserDetailsService {
@Autowired private UserDao dao;
@Autowired private Assembler assembler;
@Transactional(readOnly = true)
public UserDetails loadUserByUsername(String username)
throws UsernameNotFoundException, DataAccessException {
UserDetails userDetails = null;
UserEntity userEntity = dao.findByName(username);
if (userEntity == null)
throw new UsernameNotFoundException("user not found");
return assembler.buildUserFromUserEntity(userEntity);
}
}
Service to convert your entity to a spring user object:
import org.springframework.security.core.GrantedAuthority;
import org.springframework.security.core.authority.GrantedAuthorityImpl;
import org.springframework.security.core.userdetails.User;
@Service("assembler")
public class Assembler {
@Transactional(readOnly = true)
User buildUserFromUserEntity(UserEntity userEntity) {
String username = userEntity.getName();
String password = userEntity.getPassword();
boolean enabled = userEntity.isActive();
boolean accountNonExpired = userEntity.isActive();
boolean credentialsNonExpired = userEntity.isActive();
boolean accountNonLocked = userEntity.isActive();
Collection<GrantedAuthority> authorities = new ArrayList<GrantedAuthority>();
for (SecurityRoleEntity role : userEntity.getRoles()) {
authorities.add(new GrantedAuthorityImpl(role.getRoleName()));
}
User user = new User(username, password, enabled,
accountNonExpired, credentialsNonExpired, accountNonLocked, authorities, id);
return user;
}
}
The namespace-based application-context-security.xml would look something like:
<http>
<intercept-url pattern="/login.do*" filters="none"/>
<intercept-url pattern="/**" access="IS_AUTHENTICATED_ANONYMOUSLY" />
<form-login login-page="/login.do"
authentication-failure-url="/login.do?error=failed"
login-processing-url="/login-please.do" />
<logout logout-url="/logoff-please.do"
logout-success-url="/logoff.html" />
</http>
<beans:bean id="daoAuthenticationProvider"
class="org.springframework.security.authentication.dao.DaoAuthenticationProvider">
<beans:property name="userDetailsService" ref="userDetailsService"/>
</beans:bean>
<beans:bean id="authenticationManager"
class="org.springframework.security.authentication.ProviderManager">
<beans:property name="providers">
<beans:list>
<beans:ref local="daoAuthenticationProvider" />
</beans:list>
</beans:property>
</beans:bean>
<authentication-manager>
<authentication-provider user-service-ref="userDetailsService">
<password-encoder hash="md5"/>
</authentication-provider>
</authentication-manager>
If you're using a JDBC accessible database, then you could use the following authentication-provider and avoid creating a custom one. It cuts down the code required to 9 lines of XML:
<authentication-provider>
<jdbc-user-service data-source-ref="dataSource" users-by-username-query="select username,password from users where username=?" authorities-by-username-query="select u.username, r.authority from users u, roles r where u.userid = r.userid and u.username =?" />
</authentication-provider>
You can then setup your dataSource as follows
<bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName" value="com.mysql.jdbc.Driver" />
<property name="url" value="jdbc:mysql://localhost:3306/DB_NAME" />
<property name="username" value="root" />
<property name="password" value="password" />
</bean>
Have a look at this post: http://codehustler.org/blog/spring-security-tutorial-form-login/ It covers everything you need to know about customising Spring Security form-login.
A java configuration could look something like this
@Configuration
@EnableWebSecurity
public class SecurityConfig extends WebSecurityConfigurerAdapter {
@Autowired
private UserDetailsServiceImpl userDetailsService;
@Autowired
public void configureGlobal(AuthenticationManagerBuilder auth)
throws Exception {
DaoAuthenticationProvider daoAuthenticationProvider =
new DaoAuthenticationProvider();
daoAuthenticationProvider
.setUserDetailsService(userDetailsService);
auth.authenticationProvider(daoAuthenticationProvider);
}
}
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