Can regular expressions be used to perform arithmetic开发者_JAVA百科? Such as find all numbers in a file and multiply them by a scalar value.
You can achieve this using re.sub()
with a callback:
import re
def repl(matchobj):
i = int(matchobj.group(0))
return str(i * 2)
print re.sub(r'\d+', repl, '1 a20 300c')
Output:
2 a40 600c
From the docs:
re.sub(pattern, repl, string[, count])
If repl is a function, it is called for every non-overlapping occurrence of pattern. The function takes a single match object argument, and returns the replacement string.
In perl you can do this with the /e modifier. This causes the substitution part of the expression be evaluated. Assuming $line contains a line of the file
my $scalar= 4;
$line =~ s/([\d]+)/$1*$scalar/ge;
Applying this to every line will do the job for you. For example applying this to a $line containing "foo2 bar25 baz", transforms it to "foo8 bar100 baz"
I prepared a small script which uses re.finditer
to find all the integers (you can change the regexp so that it can deal with floats or scientific notation) and then use map
to return a list of scaled numbers.
import re
def scale(fact):
"""This function returns a lambda which will scale a number by a
factor 'fact'"""
return lambda val: fact * val
def find_and_scale(file, fact):
"""This function will find all the numbers (integers) in a file and
return a list of all such numbers scaled by a factor 'fact'"""
num = re.compile('(\d+)')
scaling = scale(fact)
f = open(file, 'r').read()
numbers = [int(m.group(1)) for m in num.finditer(f)]
return map(scaling, numbers)
if __name__ == "__main__":
import sys
if len(sys.argv) != 3:
print "usage: %s file factor" % sys.argv[0]
sys.exit(-1)
numbers = find_and_scale(sys.argv[1], int(sys.argv[2]))
for number in numbers:
print "%d " % number
If you have a file
whose numbers you want to scale by a factor fact
, you call the script from the command line as python script.py file fact
and it will print to STDOUT
all the scaled numbers. Of course, you can do something more useful if you wanted...
Regular expressions themselves can't - they're all about text - so sed can't directly. It's easy enough to do something like that in a full scripting language like python or perl, though.
To those of you who doubt that sed can do arithmetic I offer this counter-example. This one is even wilder.
Ayman Hourieh's answer can be reduced to be a little bit simpler, and imo more readable:
>>> import re
>>> repl = lambda m: str(int(m.group(0)) * 2)
>>> print re.sub(r'\d+', repl, '1 a20 300c')
2 a40 600c
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