For exmaple:
How to represent the following x86 i开发者_Python百科n SSA form:
xor eax, eax
inc ax
By introducing some pseudo functions, I come up with:
eax@1 = eax@0 ^ eax@0
ax@1 = LOWORD(eax@1)
al@1 = LOBYTE(ax@1)
ah@1 = HIBYTE(ax@1)
hax@1 = HIWORD(eax@1)
ax@2 = ax@1 + 1
eax@2 = MAKEDWORD(ax@2, HIWORD(eax@1))
al@2 = LOBYTE(ax@2)
ah@2 = HIBYTE(ax@2)
But I think it's too much verbose
Using your notation:
- eax@0 = ... whatever it was before here ...
- eax@1 = 0
- ax@2 = ax@1 + 1
Because eax contains ax, there's an implicit step in between 2 and 3
- eax@0 = ...
- eax@1 = 0
- ax@1 = 0 (because ax cannot be non-zero if eax is zero)
- ax@2 = ax@1 + 1
Step 2 because any number xor'ed with itself is 0... eax@0 is dead at that point, and thus eax@1 can be renamed (using ebx as renaming so it's readable; obviously you would use a virtual register, not a real one):
- --- deleted, eax no longer relevant
- ebx@0 = 0
- bx@0 = 0
- bx@1 = bx@0 + 1
You could then note that because step 3 is a constant function, so is step 4 (adding a constant to a constant) and compress the two together (i.e. constant folding)
- -- deleted, eax no longer relevant
- ebx@0 = 0
- bx@0 = 1
If the upper 16 bits of ebx don't dominate anything below this, you could also delete step 2.
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