Simple way to print value of a register in x86 assembly

I need to write a program in 8086 Assembly that receives data from the user, does some mathematical calculations and prints the answer on the screen, I have written all parts of the program and all work fine but I don't know how to print the number to the screen.

At the end of all my calculation the answer is AX and it is treated as an unsigned 16 b开发者_运维百科it integer. How do I print the decimal (unsigned) value of the AX register?

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you could use the C-library function itoa, implementing it isn't that hard, basicaly, you do:

while (x){
    buff[n]==x % 10;
    x/=10;
    n++;
}

and then invert the buffer (or print character-wise backwards)

void print_number(int x);

print_number:
  buff db 15 dup(0)
  mov ax,[esp+4]
  mov bx,0
itoa_w1:

  mov cx, ax
  mod cx,10
  add cx,30h;'0'
  div ax,10
  mov buff[bx],cl
  cmp ax,0
  jnz itoa_w1

itoa_w2:
  push buff[bx]
  call putchar
  pop  ax
  cmp  bx,0
  jnz itoa_w2

ret