Argument #1 ($value) must be of type Countable|array, string given in [closed]

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I'm creating a registration form. It is declared as an array on the beginning, but it says 'string given in'. I also want to know if the code is generally OK. Here is my server.php code

<?php
session_start();

$username = "";
$email= "";
$errors= array();

if (isset($_POST['reg-user'])) {
    include('db.php');
    $username = mysqli_real_escape_string($linkDB, $_POST['username']);
    $email= mysqli_real_escape_string($linkDB, $_POST['email']);
    $password=mysqli_real_escape_string($linkDB, $_POST['password']);
    $password2=mysqli_real_escape_string($linkDB, $_POST['password2']);

    if(empty($username)) {$errors= "Username is required"; }
    if(empty($email)) {$errors= "Email is required"; }
    if(empty($password_1)) {$errors= "Password is required"; }
    if($password != $password2) {
       $errors= &qu开发者_开发知识库ot;The two passwords do not match";
    }

    $user_check_query = "SELECT * FROM users WHERE username='$username' OR email='$email' LIMIT 1";
    $result = mysqli_query($linkDB, $user_check_query);
    $user = mysqli_fetch_assoc($result);

    if ($user) {
        if ($user['username'] === $username) {
            $errors= "Username already exists";
        }

        if ($user['email'] === $email) {
            $errors= "email already exists";
        }
    }
    if (count($errors)==0) {
        $password = md5($password2);

        $query = "INSERT INTO users (username, email, password) 
                    VALUES('$username', '$email', '$password')";
        mysqli_query($linkDB, $query);
        $_SESSION['username'] = $username;
        $_SESSION['success'] = "You are now logged in";
        header('location:dashboard.php');
    }
}

    if (isset($_POST['login_user'])) {
    $username = mysqli_real_escape_string($linkDB, $_POST['username']);
    $password = mysqli_real_escape_string($linkDB, $_POST['password']);

    if (empty($username)) {
        $errors= "Username is required";
    }
    if (empty($password)) {
        $errors="Password is required";
    }
    if (count($errors) ==0) {
        $password = md5($password);


        $query = "SELECT * FROM users WHERE username='$username' AND password='$password'";
        $results = mysqli_query($linkDB, $query);
        if (mysqli_num_rows($results) == 1) {
            $logged_in_user = mysqli_fetch_assoc($results);
            if ($_SESSION['username'] = 'admin') {

                $_SESSION['user'] = $logged_in_user;
                $_SESSION['success']  = "You are now logged in";
                header('location: index_for_admin.php');
            }else{
                $_SESSION['user'] = $logged_in_user;
                $_SESSION['success']  = "You are now logged in";

                header('location:dashboard.php');
            }
        }else {
            $errors="Wrong username/password combination";
        }
    }
}

?>

and there's also the same problem in error.php file. Foreach can't be used with string

<?php
   if (count($errors) >0 ):?>
       <div class= "error">
           <?php foreach ($errors as $error) :?>
               <p><?php echo $error ?></p>
           <?php endforeach ?>
       </div>
   <?php endif ?>

I tried using count_char. It works on server.php but in error.php it says "foreach() argument must be of type array|object, string given".