I'm trying to create a file that has a list of directories that have a specific file name in them.
Let's say I'm trying to find directories that have a file named *.joe
in them. I initially tried just a simple dir /ad *.joe > dir_list.txt
, but it searches the directory names for *.joe
, so no go.
Then I concluded that a for loop was probably my best bet. I started with
for /d /r %a in ('开发者_如何学运维dir *.joe /b') do @echo %a >> dir_list.txt
and it looked like it wasn't executing the dir command. I added the "usebackq", but that seems to only work for the /F command extension.
Ideas?
Since "dir /s /b file_name
" doesn't cut it, how about the following
for /d /r %a in (*) do @if exist %a\*.scr (echo %a)
It would appear that inside a batch file the only thing that needs to be esaped is the %a giving
for /d /r %%a in (*) do @if exist %%a\*.scr (echo %%a)
This will print the directory and the file name, may or may not be helpful to you:
dir /b /s | findstr "\.joe"
findstr
uses a regexp.
Save this to search.bat
or (something else you can remember)
@echo off
setlocal EnableDelayedExpansion
set last=?
if "%1" EQU "" goto usage
for /f %%I in ('dir /s /b /o:n /a-d "%1"') do (
if !last! NEQ %%~dpI (
set last=%%~dpI
echo !last!
)
)
goto end
:usage
echo Please give search parameter.
:end
and use as follows:
search.bat *.joe >dir_list.txt
Note that it searches within the current path context. You might want to add the .bat
to a location that is in the PATH
, so you can call it from any location.
dir /s/b *.joe >> dir_list.txt
and then a skript in e.g. gawk to get rid of the filenames after the dirnames
精彩评论