I am trying to use \ifthenelse to do a floating point comparison. This is the pgf/tikz code, which works if \y is integer only, but not otherwise:
\foreach \y in {3,3.5,...,6}开发者_C百科 {
ifthenelse{\y<3}{
...
}{
...
}
}
You can not use floating variables. Use dimens instead of. For example
\newdimen \y
\y = 3.2pt
\ifdim \y < 3.45pt ... \else ... \fi
To expand on Alexey's suggestion of using dimensions, here is some working TikZ code that I think will solve your problem:
\documentclass{article}
\usepackage{tikz}
\usepackage{ifthen}
\begin{document}
\begin{tikzpicture}
\foreach \y in {3,3.5,...,6} {
\ifthenelse{\lengthtest{\y pt > 4.5pt}}{
\node at (0,\y) {\y\ is greater than 4.5!};
}{
\node at (0,\y) {\y\ is less than 4.5};
}
}
\end{tikzpicture}
\end{document}
If you already have defined some float you can use the following trick which worked for me (based on Alexeys post):
\def\someFloat{1.5}
% prepare comparison by building a dummy dim value
\newdimen\dummyDim
\dummyDim = \someFloat pt
% compare:
\ifdim \dummyDim > 0pt %
% ...
\else
% ...
\fi
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