Regex: Getting content from URL

I want to get "the-game" using regex from URLs like

• http://www.somesite.com.domain.webdev.domain.com/en/the-game/another-one/another-one/another-one/
• http://www.somesite.com.domain.webdev.domain.com/en/the-game/another-one/another-one/
• http://www.somesite.com.domain.webdev.domain.com/en/the开发者_高级运维-game/another-one/

---

What parts of the URL could vary and what parts are constant? The following regex will always match whatever is in the slashes following "/en/" - the-game in your example.

(?<=/en/).*?(?=/)

This one will match the contents of the 2nd set of slashes of any URL containing "webdev", assuming the first set of slashes contains a 2 or 3 character language code.

(?<=.*?webdev.*?/.{2,3}/).*?(?=/)

Hopefully you can tweak these examples to accomplish what you're looking for.

---

var myregexp = /^(?:[^\/]*\/){4}([^\/]+)/;
var match = myregexp.exec(subject);
if (match != null) {
    result = match[1];
} else {
    result = "";
}

matches whatever lies between the fourth and fifth slash and stores the result in the variable result.

---

You probably should use some kind of url parsing library rather than resorting to using regex.

In python:

from urlparse import urlparse
url = urlparse('http://www.somesite.com.domain.webdev.domain.com/en/the-game/another-one/another-one/another-one/')
print url.path

Which would yield:

/en/the-game/another-one/another-one/another-one/

From there, you can do simple things like stripping /en/ from the beginning of the path. Otherwise, you're bound to do something wrong with a regular expression. Don't reinvent the wheel!