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redefine __and__ operator

开发者 https://www.devze.com 2022-12-27 15:26 出处:网络
Why I can\'t redefine the __and__ operator? class Cut(object): def __init__(self, cut): self.cut = cut def __and__(self, other):

Why I can't redefine the __and__ operator?

class Cut(object):
      def __init__(self, cut):
         self.cut = cut
      def __and__(self, other):
         return Cut("(" + self.cut + ") && (" + o开发者_JAVA百科ther.cut + ")")

a = Cut("a>0") 
b = Cut("b>0")
c = a and b
print c.cut()

I want (a>0) && (b>0), but I got b, that the usual behaviour of and


__and__ is the binary (bitwise) & operator, not the logical and operator.

Because the and operator is a short-circuit operator, it can't be implemented as a function. That is, if the first argument is false, the second argument isn't evaluated at all. If you try to implement that as a function, both arguments have to be evaluated before the function can be invoked.


because you cannot redefine a keyword (that's what and is) in Python. __add__ is used to do something else:

These methods are called to implement the binary arithmetic operations (...&...

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