In our code there is a function defined as:
a.h
extern int (*get_prof_action(void))(void);
a.c
static int (*ProfAct开发者_Go百科ion)(void) = NULL;
int (*get_prof_action(void))(void)
{
return ProfAction;
}
Then later in main.c, I want to gain this function through dlsym(I have to), so I used like this.
...
int (*p_get_prof_action(void))(void);
...
void my_function(){
...
void *handle=dlopen(mylibrary,RTLD_LAZY);
p_get_prof_action = (int (*(void))(void)) dlsym(handle,"get_prof_action");
...
}
And I got compile error:
error: cast specifies function type at line
(int (*(void))(void)) dlsym(handle,"get_prof_action");
=======================================================
Here are my questions:
This is not my code and I never saw such usage to define a function. Could you let me know what is this?
How do I correctly get this p_get_prof_action?
Thanks very much. This really stucks me a lot!!
You've declared p_get_prof_action
as a function, not a function pointer. The correct declaration would be:
int (*(*p_get_prof_action)(void))(void);
And the correct cast would be:
p_get_prof_action = (int (*(*)(void))(void)) dlsym(handle,"get_prof_action")
When dealing with function pointers, a typedef
can be very helpful. The function in question is returning a function pointer, so let's make one for the return type:
typedef int (*action)(void);
Then declare your function pointer to return that type:
action (*p_get_prof_action)(void);
And assign to it like this:
p_get_prof_action = (action (*)(void))dlsym(handle,"get_prof_action");
精彩评论