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django + xmppy: send a message to two recipients

开发者 https://www.devze.com 2022-12-27 00:48 出处:网络
I\'m trying to use xmpppy for sending jabber-messages from a django-website. This works entirely fine.

I'm trying to use xmpppy for sending jabber-messages from a django-website. This works entirely fine.

However, the message only gets sent to the -first- of the recipients in the list. This happens when I run the following function from django, and also if I run it from an interactive python-shell. The weird part though, is that if I extract the -body- of the function and run that interactively, then all the recipients (there's just 2 at the moment) get the message.

Also, I do know that the inner for-loop gets run the correct count times (2), because the print-statement does run twice, and return two different message-ids.

The function looks like this:

def hello_jabber(request, text):
    jid=xmpp.protocol.JID(settings.JABBER_ID)
    cl=xmpp.Client(jid开发者_StackOverflow社区.getDomain(),debug=[])
    con=cl.connect()
    auth=cl.auth(jid.getNode(),settings.JABBER_PW,resource=jid.getResource())
    for friend in settings.JABBER_FRIENDS:
        id=cl.send(xmpp.protocol.Message(friend,friend + ' is awesome:' + text))
        print 'sent message with id ' + str(id)
    cl.disconnect()
    return render_to_response('jabber/sent.htm', locals())


Activate the debug options in xmpppy to see what does the xmpp client.

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