开发者

Wait before firing a function to execute in JavaScript

开发者 https://www.devze.com 2022-12-26 20:47 出处:网络
How can I set a delayed trigger in JavaScript to execute a function after a specified amount of time?

How can I set a delayed trigger in JavaScript to execute a function after a specified amount of time?

My program will wait for 5 seconds to execute demo(); and if it 开发者_运维问答fails to start demo within 5 seconds I need to execute sample() automatically.

Is this possible to do in JavaScript?


You can invoke functions after a period of time with setTimeout

setTimeout(demo, 5000);

I'm not sure that I get the "if it is fail to start demo with in 5 seconds" part of your question, because the above code will execute demo() in 5 seconds.


Have a look at:

  • setInterval
  • setTimeout
  • clearInterval

Example:

setTimeout(function(){your code here}, 3000)


<script language="javascript">
function sample() {
  alert('sample here');
}
function demo() {
  alert('demo here');
}
setTimeout("sample()", 5000);
</script>

<input type=button onclick="demo();">


You can use setTimeout for a pause in javascript.

setTimeout(function(){callSample();}, 5000);

then set a global variable inside demo() so that you can identify whether demo() has been called or not and then in

function callSample()
{
    if (variable set)
    {
        sample();
    }
}
0

精彩评论

暂无评论...
验证码 换一张
取 消