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Handling two WebException's properly [closed]

开发者 https://www.devze.com 2022-12-26 20:39 出处:网络
Closed. This question is opinion-based. It is not currently accepting answers. 开发者_如何学Python
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开发者_如何学Python

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I am trying to handle two different WebException's properly.

Basically they are handled after calling WebClient.DownloadFile(string address, string fileName)

AFAIK, so far there are two I have to handle, both WebException's:

  • The remote name could not be resolved (i.e. No network connectivity to access server to download file)
  • (404) File not nound (i.e. the file doesn't exist on the server)

There may be more but this is what I've found most important so far.

So how should I handle this properly, as they are both WebException's but I want to handle each case above differently.

This is what I have so far:

try
{
    using (var client = new WebClient())
    {
        client.DownloadFile("...");
    }
}
catch(InvalidOperationException ioEx)
{
    if (ioEx is WebException)
    {
        if (ioEx.Message.Contains("404")
        {
            //handle 404
        }
        if (ioEx.Message.Contains("remote name could not")
        {
            //handle file doesn't exist
        }
    }
}

As you can see I am checking the message to see what type of WebException it is. I would assume there is a better or a more precise way to do this?


Based on this MSDN article, you could do something along the following lines:

try
{
    // try to download file here
}
catch (WebException ex)
{
    if (ex.Status == WebExceptionStatus.ProtocolError)
    {
        if (((HttpWebResponse)ex.Response).StatusCode == HttpStatusCode.NotFound)
        {
            // handle the 404 here
        }
    }
    else if (ex.Status == WebExceptionStatus.NameResolutionFailure)
    {
        // handle name resolution failure
    }
}

I'm not certain that WebExceptionStatus.NameResolutionFailure is the error you are seeing, but you can examine the exception that is thrown and determine what the WebExceptionStatus for that error is.

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