javascript sum of two numbers inside an array print index of numbers whoose sum = target

[https://drive.google.com/file/d/12qIWazKzBr1yJGpo1z106euXVJMKMwEa/view?usp=sharing][1]i have to find the index of two numbers whoose sum = target[number given as argument] i have tried to solve this through for loop but i am not getting the indexex correctly as if the first two numbers of array are 1,1 and target is set as two i am getting answer as [0,0] but i want [0,1]

let arr = [1,1,8,9,7,22,6]




var twoSum = function(nums, target开发者_开发百科) {
    for(i=0;i<nums.length;i++){
        for(j=i+1;j<nums.length;j++)
        if(nums[i] + nums[j]==target){
           
            return [nums.indexOf(nums[i]) , nums.indexOf(nums[j])]
        }

    }
};
console.log(twoSum(arr, 2))
i am expecting output as [0,1]
but i am getting output as [0,0]


  [1]: https://i.stack.imgur.com/n1jo7.png

---

The indexOf method returns the first occurrence of a particular value. Since you have 1 in both 0 and 1 indexes, It will only return 0 because it is the first occurrence of 1.

MDN Documentation

Just return the i and j itself.

return [i, j];

---

Changes made:- Just change the return statement of yours

Code:-

let arr = [1,1,8,9,7,22,6]
var twoSum = function(nums, target) {
    for(i=0;i<nums.length;i++){
        for(j=i+1;j<nums.length;j++)
        if(nums[i] + nums[j]==target){
            return [i,j]
        }

    }
};
console.log(twoSum(arr, 2))

Output:-

node /tmp/fiXkoJ2VkT.js
[ 0, 1 ]

Note let's say you want a sum 9.[0,2] and [1,2] both sum up to give 9 but the output will be [0,2] not [1,2] as you are checking for 1st element all cases than 2nd element all cases and so on..

Updated section .. {your query}

---

let arr = [1, 1, 8, 9, 7, 22, 6];

function twoSum(arr, target) {
  for (let i = 0; i < arr.length; i++) {
    for (let j = i + 1; j < arr.length; j++) {
      if (arr[i] + arr[j] === target) console.log([i, j]);
    }
  }
}

twoSum(arr, 2);