Is there a way to use unix date
to print the number of seconds since epoch?
I'm open to using other standard shell commands if there is a way
(I'm using Solaris, so there i开发者_如何学编程sn't date "+"%s"
)
Thanks
perl -e 'print time'
Well, since this is a programming site, I would just compile something like:
#include <stdio.h>
#include <time.h>
int main (void) {
printf ("%d\n",time(0));
return 0;
}
:-)
you can try nawk,(but try to double confirm with the perl commands and see if they give the same results)
nawk "BEGIN{print srand}"
Try this
/usr/bin/truss /usr/bin/date 2>&1 | grep ^time | awk '{print $3}'
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