If we have two private varaibles of same class i.e x and y. Then we initizalize its value as 5 and 4. Then how can we add both of them.
// Online C++ compiler to run C++ program online
#include <iostream>
using namespace std;
class pukar{
int x,y;
public:
void setdata(int x1){
x=x1;
friend void add(pukar);
}
void setdata1(int y1){
y=y1;
开发者_如何学运维 }
friend void add(pukar);
};
void add(pukar o1){
cout<<"The sum is "<<o1.x+o1.y<<endl;
}
int main() {
pukar rimal;
rimal.setdata(5);
rimal.setdata1(3);
rimal.add();
return 0;
}
I tried this code but it is throwing errors.
You have three issues.
- Unexpected friend function declaration inside
pukar::setdata
. This is unnecessary and can be removed. add
accesses an undeclaredo2
. This should likely becout<<"The sum is "<<o1.x+o1.y<<endl;
- You call
add
as a member function ofpukar
rather than a standalone function. Tryadd(rimal);
instead.
While your code will work with using namespace std;
it is discouraged. Rather either fully wualify your names with std::
or use using
scoped locally.
void add(pukar o1) {
using std::cout;
using std::endl;
cout << "The sum is " << o1.x + o2.y << endl;
}
Remove friend line here
void setdata(int x1){
x=x1;
friend void add(pukar); // <--- delete this line
}
friend
can only be used at the top level within a class.
Change o2
to o1
here
void add(pukar o1){
cout<<"The sum is "<<o1.x+o2.y<<endl;
}
Here o2
is an undeclared variable.
Change this
rimal.add();
to this
add(rimal);
add
is a global function, it is not a member of the pukar
class. It's a friend of the pukar
class but that does not make it a member of the class.
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